Blood alcohol content (BAC) estimate by the Widmark formula from drinks, body weight and time, with the elimination curve and time back to zero.
更新日 検証済みの例：5
By the Widmark estimate, blood alcohol is about 0.042% now and falls to zero in roughly 2 h 47 min. This is an average-person model, not a measurement.
r = 0.73 for men: the share of body weight that holds the alcohol.
0.015 % per hour is an average elimination rate; individual rates differ.
Blood alcohol content (BAC) is estimated with the Widmark formula: the alcohol drunk is spread through a share r of body weight, 0.73 for men and 0.66 for women, and about 0.015 percentage points are eliminated per hour. In US units, BAC % = fluid ounces of alcohol × 5.14 ÷ (weight in lb × r) − 0.015 × hours. One US standard drink holds 14 g, or 0.6 fl oz, of pure alcohol (NIAAA).
People use it to see how drinks, body weight and time interact. An 80 kg man who has had 3 standard drinks over 2 hours is estimated at 0.042 %, and the estimate reaches zero about 2 h 47 min later.
The result is an average-person model, not a measurement: food, drinking pace, medicines and liver function change real BAC, and impairment begins well below legal limits. It is not a basis for deciding whether to drive.
照合元：Python 3.8 decimal: 1.8 × 5.14 / (180 × 0.73) − 0.015 × 2 = 0.04041; zero after 0.070411/0.015 − 2 h = 2.6941 h
照合元：Python 3.8 decimal: A = 750/29.5735295625 × 0.12 = 3.04326 fl oz; 3.04326 × 5.14 / (130 × 0.66) − 0.045 = 0.13731
照合元：Python 3.8 decimal: 0.6 × 5.14 / (176.37 lb × 0.73) = 0.02395 < 0.015 × 5, so the estimate is 0
照合元：Definition: A = 0 gives BAC 0
In the US, a standard drink contains 14 g (0.6 fl oz) of pure alcohol: 12 fl oz of 5 % beer, 5 fl oz of 12 % wine or 1.5 fl oz of 40 % spirits, according to NIAAA. Other countries use different sizes; a UK unit is 8 g, so one US standard drink is 1.75 UK units. A 750 mL bottle of 12 % wine holds about 71 g of alcohol, roughly 5 US standard drinks.
With the Widmark formula. The alcohol drunk is divided by body weight times r, the share of the body that holds it (0.73 for men and 0.66 for women here), and about 0.015 percentage points are subtracted for each hour since drinking began. A 180 lb man who has 3 standard drinks (1.8 fl oz of alcohol) peaks at 1.8 × 5.14 ÷ (180 × 0.73) = 0.070 % and is estimated at 0.040 % two hours later.
At the average elimination rate of about 0.015 percentage points per hour, a BAC of 0.08 % takes roughly 5 hours 20 minutes to reach zero. One US standard drink takes about 1.3 hours to clear for a 100 kg man and 2.8 hours for a 50 kg woman by this estimate. Coffee, water and sleep do not speed elimination; the liver sets the pace, and individual rates vary.
0.08 % in every US state except Utah, which lowered its limit to 0.05 % in 2018, and 0.04 % for US commercial drivers. England, Wales and Northern Ireland use 80 mg per 100 mL of blood (0.08 %) and Scotland 50 mg (0.05 %). Impairment starts below these limits, so an estimate under the limit does not mean it is safe to drive.
精度は入力値と計算方法の前提に依存します。十進演算には有効数字50桁を使いますが、推定、数値計算手法、元データの精度はそれより低い場合があります。表示の丸め処理でこれらの制約がなくなるわけではありません。 独立した出典の解答と照合した計算例：5。 例えば、「Man, 180 lb, 3 standard drinks, 2 hours」はPython 3.8 decimal: 1.8 × 5.14 / (180 × 0.73) − 0.015 × 2 = 0.04041; zero after 0.070411/0.015 − 2 h = 2.6941 hと照合しています。
Widmark EMP. Die theoretischen Grundlagen und die praktische Verwendbarkeit der gerichtlich-medizinischen Alkoholbestimmung (1932); NIAAA — What is a standard drink?; NIAAA — Understanding the dangers of alcohol overdose.
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この計算機には、独立した出典の解答を使った計算例が 5 件あります。テストに組み込まれており、ここでも実行できます。
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