円の計算:面積・円周・半径

面積、円周、半径、直径のいずれか1つから残りを計算。中心角から弧長、弦長、扇形と弓形の面積も求めます。

更新日 検証済みの例:6

0°から360°の間
試す
面積
cm²
面積: 78.5398 cm²
小数点以下の最大桁数:4;最も近い値へ、等距離ならゼロから遠い値へ
半径
5cm
直径
10cm
円周
31.4159cm
弧の長さ
5.236cm
弦の長さ
5cm
扇形の面積
13.09cm²
弓形の面積
2.2647cm²

A circle of radius 5 cm has diameter 10 cm, circumference 31.4159 cm and area 78.5398 cm². A 60° arc of it is 5.236 cm long, and the chord joining its ends is 5 cm.

Circle, sector and chord

r = 5 cmd = 10 cm60°arc 5.236 cmO
計算方法 S
  1. 半径

    r=5 cmr = 5\,\text{cm}
  2. Diameter and circumference

    d=2r=10 cm,C=2πr=2π×5=31.415927 cmd = 2r = 10\,\text{cm},\qquad C = 2\pi r = 2\pi \times 5 = 31.415927\,\text{cm}
  3. 面積

    A=πr2=π×52=78.539816 cm2A = \pi r^2 = \pi \times 5^2 = 78.539816\,\text{cm}^{2}
  4. Arc length and chord

    s=rθ=5×60π180=5.235988 cm,c=2rsin⁡θ2=2×5×sin⁡30∘=5 cms = r\theta = 5 \times \frac{60\pi}{180} = 5.235988\,\text{cm},\qquad c = 2r\sin\frac{\theta}{2} = 2 \times 5 \times \sin 30^\circ = 5\,\text{cm}
  5. Sector and segment areas

    Asector=πr2θ360∘=13.089969 cm2,Asegment=r22(θ−sin⁡θ)=2.264652 cm2A_\text{sector} = \pi r^2 \frac{\theta}{360^\circ} = 13.089969\,\text{cm}^{2},\qquad A_\text{segment} = \frac{r^2}{2}\left(\theta - \sin\theta\right) = 2.264652\,\text{cm}^{2}

    The segment is the region between the chord and the arc; θ is in radians inside the bracket.

円の計算:面積・円周・半径について

Give any one of the radius, diameter, circumference or area and the other three follow from d = 2r, C = 2πr and A = πr². For a central angle θ the calculator also returns the arc length s = rθ (θ in radians), the chord c = 2r sin(θ/2), the sector area πr² × θ/360° and the segment area r²/2 × (θ − sin θ).

The default radius of 5 cm gives a diameter of 10 cm, a circumference of 31.4159 cm and an area of 78.5398 cm². Its 60° arc is 5.236 cm long and the chord across it is exactly 5 cm, because two radii and that chord form an equilateral triangle. Starting from the circumference suits trees, pipes and columns whose diameter cannot be reached: a girth of 100 cm means a diameter of 31.831 cm.

Inputs can be in any length or area unit, including hectares and acres, and every result appears in the unit chosen under "Show results in". The central angle must be above 0° and at most 360°; at 360° the segment is the whole disc.

計算例

半径 5 cm、円弧 60°

既知の値
半径
半径
5 cm
弧と弦に対応する中心角
60 °
結果の単位
センチメートル (cm)
面積
78.539816 cm²
円周
31.415927 cm
直径
10 cm
弧の長さ
5.235988 cm
弦の長さ
5 cm
扇形の面積
13.089969 cm²

照合元:Python 3.8 math: pi*5**2, 2*pi*5, 5*radians(60), 2*5*sin(radians(30)) = 5 (equilateral triangle), pi*25*60/360

円周 100 cm

既知の値
円周
円周
100 cm
弧と弦に対応する中心角
60 °
結果の単位
センチメートル (cm)
半径
15.915494 cm
面積
795.774715 cm²
直径
31.830989 cm

照合元:Python 3.8 math: 100/(2*pi), 100**2/(4*pi)

面積 1 m²、結果はメートル単位

既知の値
面積
面積
1 m²
弧と弦に対応する中心角
60 °
結果の単位
メートル (m)
半径
0.56419 m
円周
3.544908 m

照合元:Python 3.8 math: sqrt(1/pi), 2*sqrt(pi)

直径 12 in、四分の一の円弧

既知の値
直径
直径
12 in
弧と弦に対応する中心角
90 °
結果の単位
インチ (in)
弦の長さ
8.485281 in
扇形の面積
28.274334 in²
弓形の面積
10.274334 in²
弧の長さ
9.424778 in

照合元:Python 3.8 math: 12*sin(pi/4), 36*pi/4, 36*pi/4 − 18, 6*pi/2

よくある質問

How do you find the area of a circle from the diameter?

Use A = πd²/4, which is πr² with the radius written as half the diameter. A 10 cm diameter gives 25π ≈ 78.54 cm², and a 12 in pizza covers 36π ≈ 113.10 in². Area grows with the square of the diameter, so one 16 in pizza (201.06 in²) has more area than two 11 in pizzas together (190.07 in²).

How do you find the radius from the circumference?

Divide the circumference by 2π: r = C/(2π). A tree with a girth of 100 cm has a radius of 15.915 cm and a diameter of 31.831 cm (C/π). Foresters' diameter tapes do this division for you: their scale is graduated in units of π, so wrapping the tape round the trunk reads the diameter directly.

What is the difference between a sector and a segment of a circle?

A sector is the pie slice between two radii and the arc; a segment is the region between the arc and the chord joining its ends. The segment is the sector minus the triangle formed by the two radii and the chord. For a 90° slice of a circle with a 6 in radius, the sector is 9π ≈ 28.274 in², the triangle 18 in², and the segment 10.274 in².

How do you calculate arc length?

Multiply the radius by the central angle in radians: s = rθ. With the angle in degrees, use s = 2πr × θ/360. A 60° arc on a 5 cm radius is 5 × π/3 ≈ 5.236 cm, one sixth of the 31.416 cm circumference. Putting degrees straight into s = rθ gives an answer 57.3 times too large, the number of degrees in one radian.

Is 3.14 accurate enough for pi?

For estimates, yes. 3.14 is 0.05% below π, so a 5 cm radius gives an area of 78.5 cm² instead of 78.54 cm²; the fraction 22/7 is 0.04% too high. The absolute error grows with size: for a radius of 100 m, 3.14 gives 31,400 m², which is 15.9 m² short of the true 31,415.9 m².

「円の計算:面積・円周・半径」の精度はどのくらいですか?

精度は入力値と計算方法の前提に依存します。十進演算には有効数字50桁を使いますが、推定、数値計算手法、元データの精度はそれより低い場合があります。表示の丸め処理でこれらの制約がなくなるわけではありません。 独立した出典の解答と照合した計算例:6。 例えば、「半径 5 cm、円弧 60°」はPython 3.8 math: pi*5**2, 2*pi*5, 5*radians(60), 2*5*sin(radians(30)) = 5 (equilateral triangle), pi*25*60/360と照合しています。

この計算方法の出典は何ですか?

Weisstein, E. W. “Circle”, “Circular Segment” — MathWorld; NIST Digital Library of Mathematical Functions §3.12 — mathematical constant π.

この計算機について

A=πr2,C=2πr,s=rθc=2rsin⁡θ2,Asegment=r22(θ−sin⁡θ)\begin{gathered} A = \pi r^2,\quad C = 2\pi r,\quad s = r\theta \\ c = 2r\sin\tfrac{\theta}{2},\quad A_\text{segment} = \tfrac{r^2}{2}(\theta - \sin\theta) \end{gathered}

出典

  1. Weisstein, E. W. “Circle”, “Circular Segment” — MathWorld
  2. NIST Digital Library of Mathematical Functions §3.12 — mathematical constant π

出典と照合済み

この計算機には、独立した出典の解答を使った計算例が 6 件あります。テストに組み込まれており、ここでも実行できます。

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