Pool volume and tank capacity calculator

Pool volume in gallons, litres and m³ for rectangular, round or oval pools and water tanks, with fill time and the chlorine dose to raise ppm.

Обновлено Проверенные примеры: 5

A garden hose gives roughly 20–40 L/min (5–10 gal/min).
ppm
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Water volume
L
Water volume: 75,000 L
Максимум знаков после запятой: 1; До ближайшего, при равенстве — от нуля
Water volume
19,812.9US gal / 75m³
Time to fill
1 d 17 h 40 min
Liquid chlorine to add
1.2L / 40.58US fl oz
The average of the two ends assumes the floor slopes evenly; a pool with a hopper or steps holds a little less.

It holds 75,000 L (19,813 US gal) and fills in about 1 d 17 h 40 min at 30 L/min. Raising chlorine by 2 ppm takes 1.2 L of liquid chlorine 12.5%.

Side section (sloping floor)

10 m1 m2 m
Как выполняется расчёт S
  1. Объём

    10×5×1+22=75 m310 \times 5 \times \frac{1 + 2}{2} = 75\ \text{m}^3
  2. Litres and gallons

    75 m3=75,000 L=19,812.903927 US gal75\ \text{m}^3 = 75{,}000\ \text{L} = 19{,}812.903927\ \text{US gal}
  3. Fill time

    75,000 L30 L/min=2,500 min\frac{75{,}000\ \text{L}}{30\ \text{L/min}} = 2{,}500\ \text{min}

    1 d 17 h 40 min

  4. Chlorine dose

    2 mg/L×75,000 L=150 g÷125 g/L=1.2 L2\ \text{mg/L} \times 75{,}000\ \text{L} = 150\ \text{g} \div 125\ \text{g/L} = 1.2\ \text{L}

    Liquid strength is the trade percentage: 12.5% means 125 g of available chlorine per litre.

О калькуляторе: Pool volume and tank capacity calculator

Volume is the water's surface area times its depth: length × width × average depth for a rectangular pool with a sloping floor, π × radius² × depth for a round pool or upright tank, and π/4 × length × width × depth for an oval. The result is given in litres, US gallons and cubic metres, and the fill time is the volume divided by the flow rate.

The default 10 × 5 m pool, 1 m deep at one end and 2 m at the other, holds 75,000 L (19,813 US gallons) and takes about 42 hours to fill at 30 L/min. Raising its free chlorine by 2 ppm needs 150 g of available chlorine, which is 1.2 L of 12.5% liquid.

One ppm is 1 mg of available chlorine per litre, and the product amount is that mass divided by its strength. Liquid strength is read as trade percent, grams per 100 mL, so 12.5% liquid carries 125 g per litre.

Примеры с решением

10 × 5 m pool, 1 m to 2 m deep, +2 ppm with 12.5% liquid

Shape
Rectangular pool
Длина
10 m
Ширина
5 m
Shallow end depth
1 m
Deep end depth
2 m
Fill rate
30 L/min
Raise free chlorine by
2 ppm
Chlorine product
Liquid chlorine 12.5%
Water volume
75,000 L
Water volume
19,812.9 US gal
Time to fill
1 d 17 h 40 min
Liquid chlorine to add
1.2 L
Liquid chlorine to add
40.58 US fl oz

Источник проверки: Python decimal: 10 × 5 × 1.5 = 75 m³; 75,000 L ÷ 30 L/min = 2,500 min; 2 mg/L × 75,000 L = 150 g ÷ 125 g/L = 1.2 L

24 ft round pool, 4 ft deep, 9 gal/min hose, +1 ppm cal-hypo 65%

Shape
Round pool
Диаметр
24 ft
Water depth
4 ft
Fill rate
9 gal/min
Raise free chlorine by
1 ppm
Chlorine product
Cal-hypo 65% (granular)
Water volume
13,536.4 US gal
Time to fill
1 d 1 h 4 min 2 s
Chlorine product to add
78.8 g
Chlorine product to add
2.78 oz

Источник проверки: Python decimal: π × 12² × 4 ft³ = 13,536 US gal; 51,241 g ÷ 1000 ÷ 0.65 = 78.8 g (Clean Pool Math: 2.1 oz per 10,000 gal·ppm → 2.8 oz)

Upright tank 1 m across, 1.2 m of water, 10 L/min

Shape
Cylindrical tank (upright)
Диаметр
1 m
Water depth
1.2 m
Fill rate
10 L/min
Raise free chlorine by
0 ppm
Chlorine product
Liquid chlorine 12.5%
Water volume
942.5 L
Time to fill
1 h 34 min 14 s
Liquid chlorine to add
0 L

Источник проверки: Python decimal: π × 0.5² × 1.2 = 0.942478 m³; 942.48 L ÷ 10 L/min = 94.25 min

30 × 15 ft oval, 4 ft deep, +3 ppm with 10% liquid

Shape
Oval pool
Длина
30 ft
Ширина
15 ft
Water depth
4 ft
Fill rate
30 L/min
Raise free chlorine by
3 ppm
Chlorine product
Liquid chlorine 10%
Water volume
10,575.3 US gal
Liquid chlorine to add
1.201 L

Источник проверки: Python decimal: π/4 × 30 × 15 × 4 = 1,413.7 ft³ = 10,575 gal (industry shortcut L × W × D × 5.9 gives 10,620)

Вопросы

How do you calculate pool volume in gallons?

Multiply length × width × average depth in feet to get cubic feet, then multiply by 7.48, the number of US gallons in a cubic foot (1,728 ÷ 231 cubic inches). A 30 × 15 ft pool averaging 5 ft deep holds 2,250 ft³, or 16,831 gallons. For a round pool use π × radius² × depth: 24 ft across and 4 ft deep holds 13,536 gallons.

How many litres of water are in a pool?

Multiply length × width × average depth in metres, then by 1,000, since a cubic metre holds 1,000 litres. A 10 × 5 m pool sloping from 1 m to 2 m has an average depth of 1.5 m, so it holds 75 m³, or 75,000 L. A round pool 5 m across with 1.2 m of water holds π × 2.5² × 1.2 = 23.6 m³, or 23,562 L.

How do you find the volume of an oval pool?

Multiply length × width × depth by π/4, about 0.785, because an ellipse covers π/4 of the rectangle around it. A 30 × 15 ft oval with 4 ft of water holds 1,413.7 ft³, or 10,575 US gallons. The common shortcut of length × width × depth × 5.9 gives 10,620 gallons, because 5.9 rounds up 0.785 × 7.48 = 5.875.

How much chlorine raises a pool by 1 ppm?

One ppm needs 1 mg of available chlorine per litre, so 10,000 US gallons (37,854 L) needs 37.9 g: about 10.2 fl oz of 12.5% liquid, 12.8 fl oz of 10% liquid or 2.1 oz of 65% cal-hypo. The CDC advises keeping free chlorine at 1 ppm or more in pools and 3 ppm or more in hot tubs, with pH between 7.0 and 7.8.

How long does it take to fill a pool with a hose?

Divide the volume by the flow rate. At 30 L/min the default 75,000 L pool takes 2,500 minutes, about 41 h 40 min, and at 9 US gallons a minute a 13,536-gallon round pool takes about 25 hours. To find your own flow rate, time how long the hose takes to fill a bucket of known size and divide the volume by the minutes.

Насколько точен «Pool volume and tank capacity calculator»?

Точность зависит от введённых данных и допущений метода. Десятичная арифметика использует 50 значащих цифр, но оценки, численные методы и исходные данные могут быть менее точными; округление на экране не устраняет эти ограничения. Решённые примеры, проверенные по независимым источникам: 5. Например, «10 × 5 m pool, 1 m to 2 m deep, +2 ppm with 12.5% liquid» проверяется по источнику Python decimal: 10 × 5 × 1.5 = 75 m³; 75,000 L ÷ 30 L/min = 2,500 min; 2 mg/L × 75,000 L = 150 g ÷ 125 g/L = 1.2 L.

Откуда взята методика?

Clean Pool Math — chlorine per 10,000 gal per 1 ppm: 13 fl oz of 10% liquid, 2.1 oz of 65% cal-hypo, 2.4 oz of 56% dichlor; PHTA — Sodium hypochlorite (liquid chlorine) fact sheet; CDC — Operating public pools, hot tubs and splash pads (free chlorine and pH levels).

Об этом калькуляторе

Vrect=ℓwd1+d22, Vround=πr2d, Voval=π4ℓwd,mCl=ppm×VL mgV_{\text{rect}} = \ell w \tfrac{d_1 + d_2}{2},\ V_{\text{round}} = \pi r^2 d,\ V_{\text{oval}} = \tfrac{\pi}{4}\ell w d,\qquad m_{\text{Cl}} = \text{ppm} \times V_{\text{L}}\ \text{mg}

Источники

  1. Clean Pool Math — chlorine per 10,000 gal per 1 ppm: 13 fl oz of 10% liquid, 2.1 oz of 65% cal-hypo, 2.4 oz of 56% dichlor
  2. PHTA — Sodium hypochlorite (liquid chlorine) fact sheet
  3. CDC — Operating public pools, hot tubs and splash pads (free chlorine and pH levels)

Проверено по источникам

В калькулятор включены решённые примеры с ответами из независимых источников. Их количество: 5. Они входят в набор тестов, и вы также можете запустить их здесь.

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