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Series and parallel resistor calculator

Series and parallel resistor calculator: total resistance of any number of resistors, plus capacitors or inductors in series or parallel.

ನವೀಕರಿಸಲಾಗಿದೆ ಪರಿಶೀಲಿಸಿದ ಉದಾಹರಣೆಗಳು: 7

Separate with commas or spaces; 4.7k works for kilo
ಪ್ರಯತ್ನಿಸಿ
Equivalent value
Ω
Equivalent value: 59.9768 Ω
ಸಾರ್ಥಕ ಅಂಕೆಗಳು: 6; ಹತ್ತಿರದ ಮೌಲ್ಯಕ್ಕೆ; ಸಮದೂರದಲ್ಲಿದ್ದರೆ ಸೊನ್ನೆಯಿಂದ ದೂರಕ್ಕೆ
Number of components
3

3 resistors in parallel act like one of 59.9768 Ω — always smaller than the smallest single part.

3 resistors in parallel: 59.9768 Ω

AB100 Ω220 Ω470 Ω
ಲೆಕ್ಕಾಚಾರದ ವಿಧಾನ S

  1. Resistors in parallel

    1Req=1100+1220+1470  ⇒  Req=59.9768 Ω\frac{1}{R_{\text{eq}}} = \frac{1}{100} + \frac{1}{220} + \frac{1}{470} \;\Rightarrow\; R_{\text{eq}} = 59.9768\ \mathrm{\Omega}

    Reciprocals add.

Series and parallel resistor calculator ಬಗ್ಗೆ

Resistors add in series, R = R₁ + R₂ + …, while in parallel their reciprocals add, 1/R = 1/R₁ + 1/R₂ + … . Inductors follow the same two rules when their magnetic fields do not interact. Capacitors do the opposite: they add in parallel and combine by reciprocals in series. Enter any number of values in one unit; 4.7k is read as 4,700.

The default, 100 Ω, 220 Ω and 470 Ω in parallel, gives 59.98 Ω, below the smallest part as every parallel network must be; the same three in series give 790 Ω. Combining parts is how a value outside the E-series is built, such as 500 Ω from two 1 kΩ resistors in parallel.

The parts are treated as ideal: no lead or contact resistance, no capacitor leakage and no mutual inductance between coils.

ಪರಿಹರಿಸಿದ ಉದಾಹರಣೆಗಳು

100, 220, 470 Ω in series

Components
Resistors
Connected in
Series
Values
100, 220, 470
ಏಕಮಾನ
Ω
Equivalent value
790 Ω

ಪರಿಶೀಲನೆಯ ಮೂಲ: Python 3.8 decimal: 100 + 220 + 470

100, 220, 470 Ω in parallel

Components
Resistors
Connected in
Parallel
Values
100, 220, 470
ಏಕಮಾನ
Ω
Equivalent value
59.9768 Ω

ಪರಿಶೀಲನೆಯ ಮೂಲ: Python 3.8 fractions: 1/(1/100 + 1/220 + 1/470) = 25850/431 = 59.976798…

Two equal 1 kΩ in parallel

Components
Resistors
Connected in
Parallel
Values
1k 1k
ಏಕಮಾನ
Ω
Equivalent value
500 Ω

ಪರಿಶೀಲನೆಯ ಮೂಲ: R/n for n equal resistors (OpenStax UP2 §10.2)

Three 100 nF in parallel

Components
Capacitors
Connected in
Parallel
Values
100 100 100
ಏಕಮಾನ
nF
Equivalent value
300 nF

ಪರಿಶೀಲನೆಯ ಮೂಲ: Sum: 300 nF

ಪ್ರಶ್ನೆಗಳು

How do you calculate resistors in parallel?

Add the reciprocals and invert: 1/R = 1/R₁ + 1/R₂ + … . For two resistors this reduces to product over sum, R = R₁R₂/(R₁ + R₂), so 100 Ω and 220 Ω in parallel give 22,000/320 = 68.75 Ω. The total is always smaller than the smallest resistor, because each extra path carries more current.

What is the resistance of equal resistors in parallel?

Divide one resistor's value by the number of resistors: n equal resistors R in parallel give R/n. Two 1 kΩ resistors give 500 Ω and four 100 Ω resistors give 25 Ω. They share the current equally, so the power ratings add too: four ¼ W resistors in parallel can dissipate 1 W between them.

How do you add capacitors in series and in parallel?

In parallel, capacitances add directly: three 100 nF capacitors give 300 nF. In series, the reciprocals add, 1/C = 1/C₁ + 1/C₂, so 10 µF and 22 µF give 6.875 µF, less than the smaller part. Series capacitors carry the same charge, so the smaller capacitor takes the larger share of the voltage.

Do inductors add like resistors?

Yes, when their magnetic fields do not couple: L = L₁ + L₂ in series and 1/L = 1/L₁ + 1/L₂ in parallel, so 10 mH and 4.7 mH in series give 14.7 mH. Coils that share flux add or subtract a mutual-inductance term of 2M in series, depending on winding direction, which this calculator does not model.

“Series and parallel resistor calculator” ಎಷ್ಟು ನಿಖರವಾಗಿದೆ?

ನಿಖರತೆ ನಿಮ್ಮ ಇನ್‌ಪುಟ್‌ಗಳು ಮತ್ತು ವಿಧಾನದ ಊಹೆಗಳನ್ನು ಅವಲಂಬಿಸಿದೆ. ದಶಮಾಂಶ ಗಣನೆ 50 ಸಾರ್ಥಕ ಅಂಕೆಗಳನ್ನು ಬಳಸುತ್ತದೆ. ಆದರೆ ಅಂದಾಜುಗಳು, ಸಂಖ್ಯಾತ್ಮಕ ವಿಧಾನಗಳು ಮತ್ತು ಮೂಲ ದತ್ತಾಂಶ ಕಡಿಮೆ ನಿಖರವಾಗಿರಬಹುದು; ಪ್ರದರ್ಶಿತ ಮೌಲ್ಯಗಳನ್ನು ರೌಂಡ್ ಮಾಡುವುದರಿಂದ ಈ ಮಿತಿಗಳು ನಿವಾರಣೆಯಾಗುವುದಿಲ್ಲ. ಸ್ವತಂತ್ರ ಮೂಲಗಳ ಪರಿಹಾರಗಳೊಂದಿಗೆ ಪರಿಶೀಲಿಸಿದ ಉದಾಹರಣೆಗಳು: 7. ಉದಾಹರಣೆಗೆ, “100, 220, 470 Ω in series” ಅನ್ನು Python 3.8 decimal: 100 + 220 + 470 ಜೊತೆಗೆ ಪರಿಶೀಲಿಸಲಾಗುತ್ತದೆ.

ಈ ವಿಧಾನದ ಮೂಲ ಯಾವುದು?

OpenStax University Physics Volume 2, §10.2 Resistors in series and parallel; §8.2 Capacitors in series and in parallel; HyperPhysics — Inductors in series and parallel (no mutual inductance).

ಈ ಕ್ಯಾಲ್ಕುಲೇಟರ್ ಬಗ್ಗೆ

Series: R=∑Ri, L=∑Li, 1C=∑1CiParallel: 1R=∑1Ri, 1L=∑1Li, C=∑Ci\text{Series: } R = \sum R_i,\ L = \sum L_i,\ \tfrac1C = \sum \tfrac1{C_i}\qquad \text{Parallel: } \tfrac1R = \sum \tfrac1{R_i},\ \tfrac1L = \sum \tfrac1{L_i},\ C = \sum C_i

ಮೂಲಗಳು

  1. OpenStax University Physics Volume 2, §10.2 Resistors in series and parallel; §8.2 Capacitors in series and in parallel
  2. HyperPhysics — Inductors in series and parallel (no mutual inductance)

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ಈ ಕ್ಯಾಲ್ಕುಲೇಟರ್‌ನಲ್ಲಿ ಸ್ವತಂತ್ರ ಆಧಾರಗಳಿಂದ ಉತ್ತರಗಳನ್ನು ಪಡೆದ 7 ಬಿಡಿಸಿದ ಉದಾಹರಣೆಗಳಿವೆ. ಇವು ಪರೀಕ್ಷಾ ಸಮೂಹದಲ್ಲಿ ನಡೆಯುತ್ತವೆ; ನೀವು ಇಲ್ಲಿಯೂ ನಡೆಸಬಹುದು.

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