Convert grams to moles and particles for any chemical formula, and find the limiting reagent, theoretical yield and leftover excess of a balanced reaction.
సార్థక అంకెలు: 6; దగ్గరి విలువ; సమదూరంలో సున్నాకు దూరంగా
ద్రవ్యరాశి
36.03g
Particles
1.20443 × 10²⁴
Molar mass used
18.015g/mol
36.03 g of H₂O is 2 mol, or 1.204 × 10²⁴ particles.
Mass, amount and particles of H₂O
గణన చేసే విధానం S
Amount in moles
n=Mm=18.01536.03=2mol
ద్రవ్యరాశి
m=nM=(2)(18.015)=36.03g
Particles
N=nNA=(2)(6.02214076×1023)=1.20443×1024
N_A is exact in the SI since 2019.
Grams to moles and stoichiometry calculator గురించి
The amount of substance links mass to particle count: n = m/M, where M is the molar mass worked out from the formula, and N = n × N_A, where the Avogadro constant N_A is 6.022 140 76 × 10²³ per mole. In limiting-reagent mode, each reactant's moles are divided by its coefficient in the balanced equation; the smallest quotient is how far the reaction can run, and it sets the theoretical yield of product.
Typical uses are weighing out reagents and predicting product mass before an experiment. The default, 36.03 g of water, is 2 mol, or 1.204 × 10²⁴ molecules. For 2 H₂ + O₂ → 2 H₂O with 10 g of hydrogen and 64 g of oxygen, oxygen runs out first and the yield is 72.06 g of water.
The yield assumes the equation is balanced and the reaction goes to completion, so measured yields come out lower.
పరిష్కరించిన ఉదాహరణలు
36.03 g of water is 2 mol
Calculate
Grams ↔ moles ↔ particles
Molar mass from
సూత్రం
సూత్రం
H2O
I have
ద్రవ్యరాశి
ద్రవ్యరాశి
36.03 g
Amount unit
mol
Amount
2 mol
Particles
1.20443 × 10²⁴
తనిఖీ చేసిన మూలం: Python 3.8 decimal: 36.03 / 18.015 = 2; × 6.02214076e23 (IUPAC 2021 weights)
One mole of carbon atoms
Calculate
Grams ↔ moles ↔ particles
Molar mass from
సూత్రం
సూత్రం
C
I have
Moles
Amount
1
Amount unit
mol
Particles
6.02214 × 10²³
ద్రవ్యరాశి
12.011 g
తనిఖీ చేసిన మూలం: SI 2019 definition of the mole (Avogadro constant exact); standard atomic weight of carbon 12.011 (IUPAC 2021)
0.25 mol NaCl with a typed molar mass
Calculate
Grams ↔ moles ↔ particles
Molar mass from
Typed value
మోలార్ ద్రవ్యరాశి
58.44 g/mol
I have
Moles
Amount
0.25
Amount unit
mol
ద్రవ్యరాశి
14.61 g
తనిఖీ చేసిన మూలం: Python 3.8 decimal: 0.25 × 58.44
3.011 × 10²³ molecules of CO₂
Calculate
Grams ↔ moles ↔ particles
Molar mass from
సూత్రం
సూత్రం
CO2
I have
Particles
Amount unit
mol
Number of particles
3.011e23
Amount
0.499988 mol
ద్రవ్యరాశి
22.004 g
తనిఖీ చేసిన మూలం: Python 3.8 decimal: 3.011e23 / N_A = 0.4999883; × 44.009 g/mol
ప్రశ్నలు
How do you convert grams to moles?
Divide the mass in grams by the molar mass in g/mol: n = m/M. Water has a molar mass of 18.015 g/mol, so 36.03 g of water is 36.03 ÷ 18.015 = 2 mol. To go back, multiply moles by the molar mass. The molar mass is the sum of the atomic weights in the formula, which the calculator adds up from IUPAC 2021 values.
What is Avogadro's number?
It is the number of particles in one mole: exactly 6.022 140 76 × 10²³ per mole since the 2019 revision of the SI, which defines the mole by fixing this constant. One mole of carbon therefore contains 6.022 140 76 × 10²³ atoms and weighs 12.011 g. Multiply an amount in moles by this number to get molecules, atoms or formula units.
How do you find the limiting reagent?
Convert each reactant's mass to moles, then divide by its coefficient in the balanced equation; the reactant with the smaller result runs out first. For N₂ + 3 H₂ → 2 NH₃ with 28 g of N₂ and 6 g of H₂, nitrogen gives 0.9995 mol ÷ 1 = 0.9995 and hydrogen gives 2.976 mol ÷ 3 = 0.992, so hydrogen limits the yield to 33.79 g of ammonia.
What is the difference between theoretical yield and percent yield?
Theoretical yield is the product mass if the limiting reagent reacted completely, which is what this calculator reports. Percent yield compares what you actually collected: actual ÷ theoretical × 100. With a theoretical yield of 72.06 g of water and 65.0 g collected, the percent yield is 90.2 %. Transfer losses, side reactions and incomplete reaction keep real yields below 100 %.
“Grams to moles and stoichiometry calculator” ఎంత కచ్చితమైనది?
కచ్చితత్వం మీ ఇన్పుట్లు, పద్ధతిలోని ఊహలపై ఆధారపడి ఉంటుంది. దశాంశ గణన 50 సార్థక అంకెలను ఉపయోగిస్తుంది. అంచనాలు, సంఖ్యా పద్ధతులు, మూల డేటా తక్కువ కచ్చితత్వంతో ఉండవచ్చు; ప్రదర్శనలో విలువలను రౌండ్ చేయడం ఈ పరిమితులను తొలగించదు. స్వతంత్ర మూలాల పరిష్కారాలతో తనిఖీ చేసిన ఉదాహరణలు: 7. ఉదాహరణకు, “36.03 g of water is 2 mol”ను Python 3.8 decimal: 36.03 / 18.015 = 2; × 6.02214076e23 (IUPAC 2021 weights)తో తనిఖీ చేశారు.
ఈ కాలిక్యులేటర్లో స్వతంత్ర ఆధారాల నుంచి సమాధానాలు పొందిన 7 సాధించిన ఉదాహరణలు ఉన్నాయి. ఇవి పరీక్షల సమూహంలో అమలవుతాయి; మీరు ఇక్కడ కూడా వాటిని అమలు చేయవచ్చు.