Grams to moles and stoichiometry calculator

Convert grams to moles and particles for any chemical formula, and find the limiting reagent, theoretical yield and leftover excess of a balanced reaction.

અપડેટ કરેલું તપાસેલાં ઉદાહરણો: 7

Used for the amount you type and the amount in the result
અજમાવો
Amount
mol
Amount: 2 mol
સૂચક અંકો: 6; સૌથી નજીક; સરખા અંતરે શૂન્યથી દૂર
દળ
36.03g
Particles
1.20443 × 10²⁴
Molar mass used
18.015g/mol

36.03 g of H₂O is 2 mol, or 1.204 × 10²⁴ particles.

Mass, amount and particles of H₂O

દળ36.03 gAmount2 molParticles1.204 × 10²⁴÷ 18.015 g/mol× 18.015 g/mol× 6.022 × 10²³÷ 6.022 × 10²³
ગણતરી કેવી રીતે થાય છે S
  1. Amount in moles

    n=mM=36.0318.015=2 moln = \frac{m}{M} = \frac{36.03}{18.015} = 2\ \mathrm{mol}
  2. દળ

    m=nM=(2)(18.015)=36.03 gm = nM = (2)(18.015) = 36.03\ \mathrm{g}
  3. Particles

    N=nNA=(2)(6.02214076×1023)=1.20443×1024N = nN_A = (2)(6.02214076\times10^{23}) = 1.20443 \times 10^{24}

    N_A is exact in the SI since 2019.

Grams to moles and stoichiometry calculator વિશે

The amount of substance links mass to particle count: n = m/M, where M is the molar mass worked out from the formula, and N = n × N_A, where the Avogadro constant N_A is 6.022 140 76 × 10²³ per mole. In limiting-reagent mode, each reactant's moles are divided by its coefficient in the balanced equation; the smallest quotient is how far the reaction can run, and it sets the theoretical yield of product.

Typical uses are weighing out reagents and predicting product mass before an experiment. The default, 36.03 g of water, is 2 mol, or 1.204 × 10²⁴ molecules. For 2 H₂ + O₂ → 2 H₂O with 10 g of hydrogen and 64 g of oxygen, oxygen runs out first and the yield is 72.06 g of water.

The yield assumes the equation is balanced and the reaction goes to completion, so measured yields come out lower.

ઉકેલેલાં ઉદાહરણો

36.03 g of water is 2 mol

Calculate
Grams ↔ moles ↔ particles
Molar mass from
સૂત્ર
સૂત્ર
H2O
I have
દળ
દળ
36.03 g
Amount unit
mol
Amount
2 mol
Particles
1.20443 × 10²⁴

ચકાસણીનો સ્ત્રોત: Python 3.8 decimal: 36.03 / 18.015 = 2; × 6.02214076e23 (IUPAC 2021 weights)

One mole of carbon atoms

Calculate
Grams ↔ moles ↔ particles
Molar mass from
સૂત્ર
સૂત્ર
C
I have
Moles
Amount
1
Amount unit
mol
Particles
6.02214 × 10²³
દળ
12.011 g

ચકાસણીનો સ્ત્રોત: SI 2019 definition of the mole (Avogadro constant exact); standard atomic weight of carbon 12.011 (IUPAC 2021)

0.25 mol NaCl with a typed molar mass

Calculate
Grams ↔ moles ↔ particles
Molar mass from
Typed value
મોલર દળ
58.44 g/mol
I have
Moles
Amount
0.25
Amount unit
mol
દળ
14.61 g

ચકાસણીનો સ્ત્રોત: Python 3.8 decimal: 0.25 × 58.44

3.011 × 10²³ molecules of CO₂

Calculate
Grams ↔ moles ↔ particles
Molar mass from
સૂત્ર
સૂત્ર
CO2
I have
Particles
Amount unit
mol
Number of particles
3.011e23
Amount
0.499988 mol
દળ
22.004 g

ચકાસણીનો સ્ત્રોત: Python 3.8 decimal: 3.011e23 / N_A = 0.4999883; × 44.009 g/mol

પ્રશ્નો

How do you convert grams to moles?

Divide the mass in grams by the molar mass in g/mol: n = m/M. Water has a molar mass of 18.015 g/mol, so 36.03 g of water is 36.03 ÷ 18.015 = 2 mol. To go back, multiply moles by the molar mass. The molar mass is the sum of the atomic weights in the formula, which the calculator adds up from IUPAC 2021 values.

What is Avogadro's number?

It is the number of particles in one mole: exactly 6.022 140 76 × 10²³ per mole since the 2019 revision of the SI, which defines the mole by fixing this constant. One mole of carbon therefore contains 6.022 140 76 × 10²³ atoms and weighs 12.011 g. Multiply an amount in moles by this number to get molecules, atoms or formula units.

How do you find the limiting reagent?

Convert each reactant's mass to moles, then divide by its coefficient in the balanced equation; the reactant with the smaller result runs out first. For N₂ + 3 H₂ → 2 NH₃ with 28 g of N₂ and 6 g of H₂, nitrogen gives 0.9995 mol ÷ 1 = 0.9995 and hydrogen gives 2.976 mol ÷ 3 = 0.992, so hydrogen limits the yield to 33.79 g of ammonia.

What is the difference between theoretical yield and percent yield?

Theoretical yield is the product mass if the limiting reagent reacted completely, which is what this calculator reports. Percent yield compares what you actually collected: actual ÷ theoretical × 100. With a theoretical yield of 72.06 g of water and 65.0 g collected, the percent yield is 90.2 %. Transfer losses, side reactions and incomplete reaction keep real yields below 100 %.

“Grams to moles and stoichiometry calculator” કેટલું ચોક્કસ છે?

ચોકસાઈ તમારા ઇનપુટ અને પદ્ધતિની ધારણાઓ પર આધારિત છે. દશાંશ ગણતરી 50 સાર્થક અંકો વાપરે છે, પરંતુ અંદાજ, સંખ્યાત્મક પદ્ધતિઓ અને મૂળ ડેટા ઓછા ચોક્કસ હોઈ શકે છે; દર્શાવેલા મૂલ્યોને રાઉન્ડ કરવાથી આ મર્યાદાઓ દૂર થતી નથી. સ્વતંત્ર સ્ત્રોતોના ઉકેલેલા ઉદાહરણો સાથે ચકાસણી: 7. ઉદાહરણ તરીકે, “36.03 g of water is 2 mol”ને Python 3.8 decimal: 36.03 / 18.015 = 2; × 6.02214076e23 (IUPAC 2021 weights) સાથે ચકાસવામાં આવે છે.

આ પદ્ધતિનો સ્ત્રોત શું છે?

CODATA 2022 / SI 2019 — Avogadro constant N_A = 6.022 140 76 × 10²³ mol⁻¹ (exact); OpenStax Chemistry 2e, §4.4 Reaction yields (limiting reactant, theoretical yield).

આ કેલ્ક્યુલેટર વિશે

n=mM,N=nNA;ξ=min⁡ ⁣(nAa,nBb),mproduct=c ξ Mproductn = \frac{m}{M},\quad N = nN_A;\qquad \xi = \min\!\left(\frac{n_A}{a}, \frac{n_B}{b}\right),\quad m_{\text{product}} = c\,\xi\,M_{\text{product}}

સ્રોતો

  1. CODATA 2022 / SI 2019 — Avogadro constant N_A = 6.022 140 76 × 10²³ mol⁻¹ (exact)
  2. OpenStax Chemistry 2e, §4.4 Reaction yields (limiting reactant, theoretical yield)

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આ કેલ્ક્યુલેટરમાં સ્વતંત્ર સ્રોતોના જવાબો ધરાવતા 7 ઉકેલેલાં ઉદાહરણો છે. તે પરીક્ષણ સમૂહમાં ચાલે છે અને તમે અહીં પણ ચલાવી શકો છો.

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