∫₀¹ e^(−x²) dx
- Function f(x)
- exp(-x^2)
- Lower limit a
- 0
- Upper limit b
- 1
- İntegral
- 0.746824132812
Doğrulama kaynağı: (√π/2)·erf(1): Python decimal, erf by its Maclaurin series at 70 digits (hp.py)
Belirli integral hesaplayıcı
The definite integral of any function f(x) between two limits, by adaptive Gauss–Kronrod quadrature to about 20 significant digits, with the area shaded.
Güncellendi Doğrulanan örnekler: 7
İntegral
İntegral: 0.746824132812
- Estimated error
- 1.1 × 10⁻²¹
- Function evaluations
- 45
- Subintervals used
- 2
The signed area between f(x) and the x-axis from 0 to 1 is 0.7468241328; area below the axis counts as negative. It took 45 evaluations over 2 subintervals.
Area under f(x) from 0 to 1
Subintervals
| Kaynak | Hedef | Contribution | Error estimate |
|---|---|---|---|
| 0 | 0.5 | 0.4613 | 3.2 × 10⁻²² |
| 0.5 | 1 | 0.2855 | 8 × 10⁻²² |
Nasıl hesaplanır S
Scale each piece to [−1, 1]
Kronrod 15-point rule with its embedded Gauss 7-point rule
The 7 Gauss nodes are reused by the 15-point rule, so the error estimate costs no extra evaluations; ρ is ∫|f − mean| over the piece (QUADPACK's scaling). Nodes and weights are carried to 52 digits.
Adaptive bisection
Split the subinterval with the largest error estimate until the total met the tolerance: 2 subintervals, 45 evaluations of f.
Sonuç
Belirli integral hesaplayıcı hakkında
A definite integral ∫ₐᵇ f(x) dx is the signed area between f and the x-axis from a to b, with area below the axis counted as negative. The calculator uses the 15-point Gauss–Kronrod rule from QUADPACK (routine QK15), which samples f at 15 points on each piece and compares the result with the embedded 7-point Gauss rule to estimate its own error. The piece with the largest error is split in two until the total estimated error falls below 10⁻²⁰ of the answer.
It suits integrals with no convenient antiderivative, such as the bell curve e^(−x²), and checking answers found by hand. The default, ∫₀¹ e^(−x²) dx, equals (√π/2)·erf(1) ≈ 0.7468241328 and took 45 evaluations of f over 2 subintervals.
Trig functions use radians, and limits accept expressions such as pi/2. Integrable endpoint singularities, like √x or ln x at 0, are handled because Gauss–Kronrod nodes never touch the endpoints. Swapping the limits flips the sign.
Çözümlü örnekler
∫₀^π sin x dx
- Function f(x)
- sin(x)
- Lower limit a
- 0
- Upper limit b
- pi
- İntegral
- 2
Doğrulama kaynağı: −cos π + cos 0 = 2 (antiderivative)
∫₁² 1/x dx
- Function f(x)
- 1/x
- Lower limit a
- 1
- Upper limit b
- 2
- İntegral
- 0.69314718056
Doğrulama kaynağı: ln 2: Python Decimal(2).ln()
∫₀³ x⁵eˣ dx
- Function f(x)
- x^5 * exp(x)
- Lower limit a
- 0
- Upper limit b
- 3
- İntegral
- 1,686.671880008638
Doğrulama kaynağı: Antiderivative eˣ(x⁵ − 5x⁴ + 20x³ − 60x² + 120x − 120) evaluated in Python decimal
Sorular
What does a definite integral represent?
The signed area between the curve and the x-axis over an interval: area above the axis counts as positive and area below as negative. ∫₀^π sin x dx = 2 because one arch of the sine curve encloses an area of 2, while ∫₀^2π sin x dx = 0 because the second arch lies below the axis and cancels the first. It is also a total change: integrating speed over time gives distance traveled.
How do you evaluate a definite integral by hand?
Find an antiderivative F with F′ = f, then subtract: ∫ₐᵇ f(x) dx = F(b) − F(a), which is the fundamental theorem of calculus. For ∫₁² 1/x dx, F(x) = ln x, so the answer is ln 2 − ln 1 ≈ 0.693147. When no elementary antiderivative exists, as for e^(−x²), a numerical rule like this one is the practical route.
What is Gauss–Kronrod quadrature?
A rule that estimates an integral from a weighted sum of f at carefully placed points. The 7-point Gauss rule integrates every polynomial up to degree 13 exactly; Kronrod's extension adds 8 more points and reuses the first 7, so comparing the two estimates gives an error bound without extra evaluations. QUADPACK's QK15 routine, used here, pairs it with repeated splitting of the worst subinterval.
What is the integral of e^(−x²)?
It has no antiderivative among elementary functions, so it is written with the error function: ∫₀ˣ e^(−t²) dt = (√π/2) erf(x). From 0 to 1 the value is about 0.7468241328, and over the whole real line it is √π ≈ 1.7724539. This Gaussian integral is what makes the normal distribution's total probability equal 1.
Can a definite integral be negative?
Yes, when more of the area lies below the x-axis than above it, or when the limits run backward. ∫₁² (−x) dx = −1.5, and the integral of x² from 1 down to 0 is −1/3, the negative of ∫₀¹ x² dx = 1/3. For the total area regardless of sign, integrate the absolute value instead: ∫₀^2π |sin x| dx = 4, entered as abs(sin(x)).
“Belirli integral hesaplayıcı” ne kadar doğru sonuç verir?
Doğruluk, girdilerinize ve yöntemin varsayımlarına bağlıdır. Ondalık aritmetik 50 anlamlı basamak kullanır; ancak tahminler, sayısal yöntemler ve kaynak veriler daha az hassas olabilir. Gösterilen değerin yuvarlanması bu sınırları ortadan kaldırmaz. Bağımsız kaynaklarla doğrulanan çözümlü örnek sayısı: 7. Örneğin “∫₀¹ e^(−x²) dx”, (√π/2)·erf(1): Python decimal, erf by its Maclaurin series at 70 digits (hp.py) ile karşılaştırılarak doğrulanır.
Yöntemin kaynağı nedir?
Piessens, de Doncker-Kapenga, Überhuber, Kahaner — QUADPACK (1983), routine QK15; Wolfram MathWorld — Gauss-Kronrod Quadrature; Laurie, Calculation of Gauss-Kronrod quadrature rules, Math. Comp. 66 (1997).
Bu hesaplayıcı hakkında
Kaynaklar
Kaynaklarla doğrulandı
Bu hesaplayıcı, yanıtları bağımsız kaynaklardan alınan 7 çözümlü örnek içerir. Bunlar test paketinde çalıştırılır; burada da çalıştırabilirsiniz.
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