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Volume et aire de surface des solides

Volume, aire de surface, hauteur oblique et capacité en litres de 14 solides : cylindres, cônes, sphères, pyramides, prismes, tores et ellipsoïdes.

Mis à jour Exemples vérifiés : 13

Essayer
Volume
cm³
Volume: 282.7433 cm³
Décimales maximales : 4 ; Au plus proche, égalités en s’éloignant de zéro
Total surface area
245.0442cm²
Lateral (curved) surface area
188.4956cm²
Base area
28.2743cm²
Capacity
0.282743L

The cylinder (r = 3 cm, h = 10 cm) holds 282.7433 cm³ — 0.2827 litres — and its outside surface is 245.0442 cm².

Cylinder (r = 3 cm, h = 10 cm)

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Comment le calcul est effectué S

  1. Volume

    V=πr2h=π×32×10=282.743339 cm3V = \pi r^2 h = \pi \times 3^2 \times 10 = 282.743339\,\text{cm}^{3}

  2. Curved surface

    Slateral=2πrh=188.495559 cm2S_\text{lateral} = 2\pi r h = 188.495559\,\text{cm}^{2}

  3. Total surface area (with both ends)

    S=2πr(r+h)=245.044227 cm2S = 2\pi r(r + h) = 245.044227\,\text{cm}^{2}

  4. Capacity

    282.743339 cm3=0.28274334 L282.743339\,\text{cm}^{3} = 0.28274334\,\text{L}

    1 L = 1000 cm³ = 0.001 m³.

À propos de Volume et aire de surface des solides

Choose one of 14 solids and enter its dimensions to get the volume and total surface area, plus the curved (lateral) surface, base area, slant height and space diagonal where the solid has them. The volume is also given as a capacity in litres, using 1 L = 1,000 cm³. The formulas are the standard ones, for example V = πr²h for a cylinder, V = ⅓πh(R² + Rr + r²) for a frustum and V = 2π²Rr² for a torus.

The default cylinder, 3 cm in radius and 10 cm tall, holds 282.743 cm³ (0.283 L) and has 245.044 cm² of surface, of which 188.496 cm² is the curved side. Volume sizes tanks, containers and concrete pours; surface area sizes paint, insulation and sheet material.

Every result is exact except the surface of a general ellipsoid, which uses Knud Thomsen's approximation, within about 1.06%. The 3D model is drawn to the proportions entered; drag it to rotate.

Exemples détaillés

Cylinder r = 3 cm, h = 10 cm

Solid
Cylinder
Rayon
3 cm
Hauteur
10 cm
Unité des résultats
Centimètres (cm)
Volume
282.743339 cm³
Total surface area
245.044227 cm²
Lateral (curved) surface area
188.495559 cm²
Capacity
0.282743 L

Source de vérification : Python 3.8 math: 90*pi, 78*pi, 60*pi; 282.743… cm³ ÷ 1000 = L

Box 6 × 4 × 10 m

Solid
Cuboid (box)
Longueur
6 m
Largeur
4 m
Hauteur
10 m
Unité des résultats
Mètres (m)
Volume
240 m³
Total surface area
248 m²
Space diagonal
12.328828 m
Capacity
240,000 L

Source de vérification : 6·4·10; 2(24 + 60 + 40); Python 3.8 math.sqrt(152); 1 m³ = 1000 L

Cone r = 3, h = 4 (slant 5)

Solid
Cone
Rayon
3 cm
Hauteur
4 cm
Unité des résultats
Centimètres (cm)
Slant height
5 cm
Volume
37.699112 cm³
Lateral (curved) surface area
47.12389 cm²
Total surface area
75.398224 cm²

Source de vérification : 3-4-5 slant; Python 3.8 math: 12*pi, 15*pi, 24*pi

Frustum R = 5, r = 3, h = 4

Solid
Frustum of a cone
Bottom radius (R)
5 cm
Top radius (r)
3 cm
Hauteur
4 cm
Unité des résultats
Centimètres (cm)
Slant height
4.472136 cm
Volume
205.25072 cm³
Total surface area
219.211186 cm²

Source de vérification : Python 3.8 math: sqrt(20), pi*4*(25+15+9)/3, pi*8*sqrt(20) + 34*pi

Questions

How do you calculate the volume of a cylinder?

Multiply the area of the circular end by the height: V = πr²h. A radius of 3 cm and a height of 10 cm give 90π ≈ 282.74 cm³, or 0.283 L. Use the radius, not the diameter: a tank 1 m across and 1.5 m tall has r = 0.5 m and holds π × 0.25 × 1.5 ≈ 1.178 m³, which is 1,178 L.

How do you find the surface area of a cylinder?

Add the curved side, 2πrh, to the two circular ends, 2πr²: S = 2πr(r + h). For r = 3 cm and h = 10 cm the curved side is 60π ≈ 188.50 cm² and the total is 78π ≈ 245.04 cm². An open-topped tank has only one end, so subtract πr², here 28.27 cm², to get 216.77 cm².

How many litres are in a cubic metre?

1,000. A litre is exactly one cubic decimetre, 1,000 cm³, a definition fixed by the General Conference on Weights and Measures (CGPM) in 1964. Divide cubic centimetres by 1,000 to get litres. In US units, one gallon is exactly 231 in³, or 3.785411784 L, and one cubic foot is 28.316846592 L.

What is the formula for the volume of a sphere?

V = ⁴⁄₃πr³, which is two thirds of the cylinder that just encloses the sphere, as Archimedes showed. A sphere of radius 3 cm holds 36π ≈ 113.10 cm³, and a ball 1 m across holds 0.5236 m³, or 523.6 L. Volume grows with the cube of the radius, so doubling the diameter multiplies the volume by 8.

How do you calculate the volume of a cone or a pyramid?

Take one third of the base area times the height: V = ⅓Bh. A cone of radius 3 and height 4 has V = ⅓π × 9 × 4 = 12π ≈ 37.70, and a square pyramid with a 6 × 6 base and height 4 has V = ⅓ × 36 × 4 = 48. A cone holds exactly one third of the cylinder with the same base and height.

Quelle est la précision de « Volume et aire de surface des solides » ?

La précision dépend de vos données et des hypothèses de la méthode. Le calcul décimal utilise 50 chiffres significatifs, mais les estimations, méthodes numériques et données sources peuvent être moins précises ; l’arrondi affiché ne supprime pas ces limites. Exemples résolus vérifiés à partir de sources indépendantes : 13. Par exemple, « Cylinder r = 3 cm, h = 10 cm » est vérifié à l’aide de Python 3.8 math: 90*pi, 78*pi, 60*pi; 282.743… cm³ ÷ 1000 = L.

D’où vient cette méthode ?

Zwillinger, D. (ed.) CRC Standard Mathematical Tables and Formulas, 33rd ed., §4.6 (solids); Weisstein, E. W. “Torus”, “Spherical Cap”, “Ellipsoid” — MathWorld; Thomsen, K. — ellipsoid surface approximation, as quoted in “Ellipsoid § Surface area”, Wikipedia.

À propos de ce calculateur

Vsphere=43πr3,Vcone=13πr2hVfrustum=13πh(R2+Rr+r2),Vtorus=2π2Rr2\begin{gathered} V_\text{sphere} = \tfrac{4}{3}\pi r^3,\quad V_\text{cone} = \tfrac{1}{3}\pi r^2 h \\ V_\text{frustum} = \tfrac{1}{3}\pi h(R^2 + Rr + r^2),\quad V_\text{torus} = 2\pi^2 R r^2 \end{gathered}

Sources

  1. Zwillinger, D. (ed.) CRC Standard Mathematical Tables and Formulas, 33rd ed., §4.6 (solids)
  2. Weisstein, E. W. “Torus”, “Spherical Cap”, “Ellipsoid” — MathWorld
  3. Thomsen, K. — ellipsoid surface approximation, as quoted in “Ellipsoid § Surface area”, Wikipedia

Vérifié avec les références

Ce calculateur comprend 13 exemples résolus dont les réponses proviennent de sources indépendantes. Ils font partie de la suite de tests et peuvent aussi être exécutés ici.

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