مفرد عوامل میں تجزیے کا کیلکولیٹر

Prime factorization of any whole number up to 60 digits, with a factor tree, a prime or composite verdict, its divisors and the nearest primes.

تازہ کاری جانچی گئی مثالیں: 6

Up to 60 digits. Expressions work too, e.g. 2^67 − 1.
آزمائیں
Prime factorization
2³ × 3² × 5
Prime factorization: 2³ × 3² × 5
Prime or composite
Composite
Number of divisors
24
Sum of divisors σ(n)
1,170
Previous prime
359
Next prime
367

360 = 2³ × 3² × 5, so it is composite with 24 divisors adding up to 1170. The nearest primes are 359 and 367.

Factor tree

360218029024531535
Divisor pairs قطاریں: 12
DivisorPaired divisor n ÷ d
1360
2180
3120
490
572
660
845
940
1036
1230
1524
1820
حساب کا طریقہ S
  1. Trial division by small primes

    divides by 2, 3\text{divides by } 2,\ 3

    Each prime is divided out as many times as it goes before moving on.

  2. Prime factorization

    360=23×32×5360 = 2^{3} \times 3^{2} \times 5
  3. Number of divisors

    d(n)=(3+1)(2+1)(1+1)=24d(n) = (3 + 1)(2 + 1)(1 + 1) = 24
  4. Sum of divisors

    σ(n)=24−12−1⋅33−13−1⋅52−15−1=1,170\sigma(n) = \frac{2^{4} - 1}{2 - 1} \cdot \frac{3^{3} - 1}{3 - 1} \cdot \frac{5^{2} - 1}{5 - 1} = 1{,}170
  5. Nearest primes

    359<360<367359 < 360 < 367

    Candidates are tested with the same Miller–Rabin check.

مفرد عوامل میں تجزیے کا کیلکولیٹر کے بارے میں

By the fundamental theorem of arithmetic, every whole number above 1 is a product of primes in exactly one way, apart from order: 360 = 2³ × 3² × 5. The calculator divides out primes below 10,000 by trial division, splits larger composite factors with Brent's version of Pollard's rho method, and proves each factor prime with a Miller–Rabin test on the first 13 prime bases, which is deterministic below 3.3 × 10²⁴ (Sorenson and Webster, 2015).

Simplifying fractions and radicals, finding common denominators, and number puzzles all start from a factorization. The exponents also count the divisors: 360 has (3 + 1)(2 + 1)(1 + 1) = 24 divisors that sum to 1,170, and the nearest primes are 359 and 367.

Numbers up to 60 digits are accepted, including expressions such as 2^67 − 1. Above 3.3 × 10²⁴ a prime verdict is labeled “probable prime”, with an error chance below 4⁻²⁰.

حل شدہ مثالیں

360

Whole number
360
Prime factorization
2³ × 3² × 5
Prime or composite
Composite
Number of divisors
24
Sum of divisors σ(n)
1,170
Previous prime
359
Next prime
367

جانچ کا ماخذ: ⁨Python 3.8 trial division and divisor enumeration (scratchpad forkA/verify.py)⁩

Project Euler problem 3

Whole number
600851475143
Prime factorization
71 × 839 × 1471 × 6857
Number of divisors
16

جانچ کا ماخذ: ⁨Project Euler #3 (largest prime factor 6857); product and primality checked in Python 3.8⁩

Cole's factorization of 2^67 − 1

Whole number
2^67-1
Prime factorization
193707721 × 761838257287
Prime or composite
Composite
Number of divisors
4

جانچ کا ماخذ: ⁨F. N. Cole, 1903 (Bull. AMS 10:134); product and primality of both factors checked by Python trial division⁩

97 is prime

Whole number
97
Prime factorization
97
Prime or composite
Prime
Number of divisors
2
Sum of divisors σ(n)
98
Previous prime
89
Next prime
101

جانچ کا ماخذ: ⁨Table of primes (OEIS A000040): 89, 97, 101⁩

سوالات

How do you find the prime factorization of a number?

Divide by the smallest prime that goes in, and repeat on the quotient until it reaches 1. For 360: 360 ÷ 2 = 180, ÷ 2 = 90, ÷ 2 = 45, ÷ 3 = 15, ÷ 3 = 5, and 5 is prime, so 360 = 2³ × 3² × 5. Only primes up to the square root of what is left need testing; if none divides it, the remainder is itself prime.

Is 1 a prime number?

No. A prime has exactly two divisors, 1 and itself, and 1 has only one. Excluding 1 keeps factorizations unique: if 1 counted as prime, 6 could be written as 2 × 3, 1 × 2 × 3, 1 × 1 × 2 × 3 and so on. 1 is neither prime nor composite, and 2 is the smallest prime and the only even one.

How do you find the number of divisors from the prime factorization?

Add 1 to each exponent and multiply. 360 = 2³ × 3² × 5¹, so it has (3 + 1)(2 + 1)(1 + 1) = 24 divisors, because each divisor uses 0 to 3 twos, 0 to 2 threes and 0 or 1 five. The sum of the divisors is a similar product: σ(360) = (2⁴ − 1)/1 × (3³ − 1)/2 × (5² − 1)/4 = 15 × 13 × 6 = 1,170.

How can you tell if a large number is prime?

Trial division up to √n is far too slow for 20-digit numbers, so the Miller–Rabin test checks a handful of bases instead. Below 3.3 × 10²⁴, passing with the first 13 primes (2 to 41) as bases proves primality (Sorenson and Webster, 2015). 2⁶¹ − 1 = 2,305,843,009,213,693,951 passes and is prime; 2⁶⁷ − 1 fails and equals 193,707,721 × 761,838,257,287.

Why does prime factorization matter in cryptography?

RSA encryption relies on multiplying two large primes being quick while factoring their product is impractically slow. NIST SP 800-57 rates a 2048-bit RSA modulus, about 617 decimal digits, as giving 112 bits of security. That is ten times the 60-digit limit here, and even within that limit Pollard's rho splits a number quickly only when one of its factors is fairly small.

“⁨مفرد عوامل میں تجزیے کا کیلکولیٹر⁩” کتنا درست ہے؟

درستی آپ کی درج کردہ قدروں اور طریقے کے مفروضوں پر منحصر ہے۔ اعشاری حساب 50 بامعنی ہندسے استعمال کرتا ہے، مگر تخمینے، عددی طریقے اور ماخذ کا ڈیٹا کم درست ہو سکتے ہیں؛ دکھائی گئی قدروں کو راؤنڈ کرنے سے یہ حدود ختم نہیں ہوتیں۔ آزاد ذرائع کی حل شدہ مثالوں سے جانچ: 6۔ مثلاً، “⁨360⁩” کو ⁨Python 3.8 trial division and divisor enumeration (scratchpad forkA/verify.py)⁩ سے جانچا جاتا ہے۔

اس طریقے کا ماخذ کیا ہے؟

Hardy & Wright, An Introduction to the Theory of Numbers, §2.10 and §16.7 (divisor functions); Sorenson & Webster (2015), Strong pseudoprimes to twelve prime bases; Brent (1980), An improved Monte Carlo factorization algorithm.

اس کیلکولیٹر کے بارے میں

n=p1e1p2e2⋯pkekd(n)=∏(ei+1)σ(n)=∏piei+1−1pi−1\begin{gathered} n = p_1^{e_1} p_2^{e_2}\cdots p_k^{e_k} \\[6pt] d(n) = \prod (e_i + 1) \\[6pt] \sigma(n) = \prod \frac{p_i^{e_i+1} - 1}{p_i - 1} \end{gathered}

ماخذ

  1. Hardy & Wright, An Introduction to the Theory of Numbers, §2.10 and §16.7 (divisor functions)
  2. Sorenson & Webster (2015), Strong pseudoprimes to twelve prime bases
  3. Brent (1980), An improved Monte Carlo factorization algorithm

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