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평면도형 넓이와 둘레 계산기

직사각형, 삼각형, 사다리꼴, 원, 타원, 정다각형, 고리 등 15개 도형의 넓이와 둘레를 구하고 비례에 맞는 그림을 확인하세요.

업데이트 검증한 예제: 16

시도하기
넓이
cm²
넓이: 40 cm²
최대 소수 자릿수: 4; 가장 가까운 값, 중간값은 0에서 먼 쪽으로
둘레
26cm
Diagonal
9.434cm

The rectangle covers 40 cm² and its boundary is 26 cm long.

The rectangle, to scale

l = 8 cmw = 5 cm
계산 방법 S

  1. 넓이

    A=l×w=8×5=40 cm2A = l \times w = 8 \times 5 = 40\,\text{cm}^{2}

  2. 둘레

    P=2(l+w)=2(8+5)=26 cmP = 2(l + w) = 2(8 + 5) = 26\,\text{cm}

  3. Diagonal

    d=l2+w2=82+52=9.433981 cmd = \sqrt{l^2 + w^2} = \sqrt{8^2 + 5^2} = 9.433981\,\text{cm}

평면도형 넓이와 둘레 계산기 소개

Choose one of 15 plane shapes and enter the dimensions that define it. The area and perimeter come back with the other lengths that shape has: diagonals, heights, arc and chord lengths, a regular polygon's apothem and circumradius, or a ring's width. A triangle from three sides uses Heron's formula, A = √(s(s − a)(s − b)(s − c)) with s half the perimeter, and a regular polygon uses A = ns²/(4 tan(180°/n)).

The default rectangle, 8 cm by 5 cm, has an area of 40 cm², a perimeter of 26 cm and a diagonal of 9.434 cm. Area sizes flooring, turf and paint; perimeter sizes fencing, edging and skirting board. The drawing is to scale, so a mistyped dimension shows up as the wrong shape.

Base and height do not fix a triangle's slanted sides, and a trapezoid needs its legs, so those two inputs give area only. An ellipse's perimeter has no closed form; Ramanujan's second approximation is used, accurate to 0.04% or better.

계산 예제

Rectangle 8 × 5 cm

Shape
Rectangle
길이
8 cm
너비
5 cm
결과 단위
센티미터 (cm)
넓이
40 cm²
둘레
26 cm
Diagonal
9.433981 cm

검증 출처: 8 × 5, 2(8 + 5); Python 3.8 math.sqrt(89)

3-4-5 triangle by Heron's formula

Shape
Triangle (three sides)
Side a
3 cm
Side b
4 cm
Side c
5 cm
결과 단위
센티미터 (cm)
넓이
6 cm²
둘레
12 cm
높이
4 cm

검증 출처: Right triangle with legs 3 and 4: ½·3·4 = 6; height onto side 3 is the other leg, 4

Regular hexagon, side 2 m

Shape
Regular polygon
Side length
2 m
Number of sides
6
결과 단위
미터 (m)
넓이
10.392305 m²
둘레
12 m
Apothem (inradius)
1.732051 m
Circumradius
2 m

검증 출처: Python 3.8 math: 6*4/(4*tan(pi/6)) = 6√3, 2/(2*tan(pi/6)) = √3; a hexagon's circumradius equals its side

Square as a regular 4-gon (exact tan 45°)

Shape
Regular polygon
Side length
3 cm
Number of sides
4
결과 단위
센티미터 (cm)
넓이
9 cm²
Apothem (inradius)
1.5 cm
Circumradius
2.12132 cm

검증 출처: Square of side 3: area 9, apothem 3/2; Python 3.8 math: 3/sqrt(2)

자주 묻는 질문

How do you find the area of a trapezoid?

Average the two parallel sides and multiply by the perpendicular height: A = (a + b)/2 × h. Bases of 10 cm and 4 cm with a height of 4 cm give 7 × 4 = 28 cm². British English calls this shape a trapezium; the formula is the same. The perimeter also needs the two slanted legs: legs of 5 cm each make it 24 cm.

How do you find the area of a triangle from three sides?

Use Heron's formula. Take the semi-perimeter s = (a + b + c)/2, then A = √(s(s − a)(s − b)(s − c)). Sides of 5, 6 and 7 cm give s = 9 and A = √(9 × 4 × 3 × 2) = √216 ≈ 14.697 cm². Three lengths only make a triangle if each is shorter than the other two combined, so 3, 4 and 8 have no area.

What is the area of a regular hexagon?

A = (3√3/2)s², about 2.598 times the side squared. A hexagon with 5 cm sides covers 64.952 cm², and one with 2 m sides covers 10.392 m². Any regular polygon with n sides of length s has A = ns²/(4 tan(180°/n)). A hexagon's circumradius equals its side, and its apothem is s√3/2 ≈ 0.866s.

Is there a formula for the perimeter of an ellipse?

Not an exact one in elementary functions: the exact perimeter is a complete elliptic integral. Ramanujan's 1914 approximation, P ≈ π(a + b)(1 + 3h/(10 + √(4 − 3h))) with h = (a − b)²/(a + b)², is off by at most 0.04%, reached only as the ellipse flattens into a line. For semi-axes of 10 and 6 it gives 51.0539977, within 1.2 × 10⁻⁹ of the exact value.

How do you convert square feet to square metres?

Multiply by 0.09290304, the square of the international foot (0.3048 m exactly, fixed in 1959). One square metre is about 10.764 ft². A 12 ft × 10 ft room is 120 ft², or 11.148 m². Area scales with the square of the length unit, so converting each side first and then multiplying gives the same result.

“평면도형 넓이와 둘레 계산기”의 정확도는 어느 정도인가요?

정확도는 입력값과 계산 방법의 가정에 따라 달라집니다. 십진 연산은 유효숫자 50자리를 사용하지만, 추정값·수치해석 방법·원본 데이터의 정밀도는 더 낮을 수 있습니다. 표시값을 반올림해도 이러한 한계는 사라지지 않습니다. 독립적인 출처의 풀이와 대조한 계산 예시: 16. 예를 들어 “Rectangle 8 × 5 cm”은 8 × 5, 2(8 + 5); Python 3.8 math.sqrt(89)와 대조해 확인합니다.

이 계산 방법의 출처는 무엇인가요?

Weisstein, E. W. “Heron's Formula”, “Regular Polygon”, “Ellipse” — MathWorld; Ramanujan, S. (1914) “Modular equations and approximations to π”, Quarterly Journal of Mathematics 45, 350–372 (perimeter approximation II); NIST Handbook 44, Appendix C — exact inch–centimetre relation (1 in = 2.54 cm).

이 계산기 소개

A△=s(s−a)(s−b)(s−c),An-gon=ns24tan⁡(π/n)Pellipse≈π(a+b)(1+3h10+4−3h)\begin{gathered} A_\triangle = \sqrt{s(s-a)(s-b)(s-c)},\quad A_{n\text{-gon}} = \frac{n s^2}{4\tan(\pi/n)} \\ P_\text{ellipse} \approx \pi(a+b)\left(1 + \frac{3h}{10 + \sqrt{4-3h}}\right) \end{gathered}

출처

  1. Weisstein, E. W. “Heron's Formula”, “Regular Polygon”, “Ellipse” — MathWorld
  2. Ramanujan, S. (1914) “Modular equations and approximations to π”, Quarterly Journal of Mathematics 45, 350–372 (perimeter approximation II)
  3. NIST Handbook 44, Appendix C — exact inch–centimetre relation (1 in = 2.54 cm)

출처와 대조하여 검증

이 계산기에는 독립적인 출처에서 답을 얻은 계산 예제가 16개 있습니다. 테스트 모음에서 실행되며 여기에서도 실행할 수 있습니다.

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