CalcOpenly

Area and perimeter calculator for 2D shapes

Area and perimeter of 15 plane shapes, from rectangles, triangles and trapezoids to circles, ellipses, regular polygons and rings, drawn to scale.

Updated Checked against 16 worked examples

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Area
cm²
Area: 40 cm²
Shown to up to 4 decimal places, half-up
Perimeter
26cm
Diagonal
9.434cm

The rectangle covers 40 cm² and its boundary is 26 cm long.

The rectangle, to scale

l = 8 cmw = 5 cm
How it's calculated S
  1. Area

    A=l×w=8×5=40 cm2A = l \times w = 8 \times 5 = 40\,\text{cm}^{2}
  2. Perimeter

    P=2(l+w)=2(8+5)=26 cmP = 2(l + w) = 2(8 + 5) = 26\,\text{cm}
  3. Diagonal

    d=l2+w2=82+52=9.433981 cmd = \sqrt{l^2 + w^2} = \sqrt{8^2 + 5^2} = 9.433981\,\text{cm}

About the area and perimeter calculator

Choose one of 15 plane shapes and enter the dimensions that define it. The area and perimeter come back with the other lengths that shape has: diagonals, heights, arc and chord lengths, a regular polygon's apothem and circumradius, or a ring's width. A triangle from three sides uses Heron's formula, A = √(s(s − a)(s − b)(s − c)) with s half the perimeter, and a regular polygon uses A = ns²/(4 tan(180°/n)).

The default rectangle, 8 cm by 5 cm, has an area of 40 cm², a perimeter of 26 cm and a diagonal of 9.434 cm. Area sizes flooring, turf and paint; perimeter sizes fencing, edging and skirting board. The drawing is to scale, so a mistyped dimension shows up as the wrong shape.

Base and height do not fix a triangle's slanted sides, and a trapezoid needs its legs, so those two inputs give area only. An ellipse's perimeter has no closed form; Ramanujan's second approximation is used, accurate to 0.04% or better.

Worked examples

Rectangle 8 × 5 cm

Shape
Rectangle
Length
8 cm
Width
5 cm
Show results in
Centimetres (cm)
Area
40 cm²
Perimeter
26 cm
Diagonal
9.433981 cm

Checked against: 8 × 5, 2(8 + 5); Python 3.8 math.sqrt(89)

3-4-5 triangle by Heron's formula

Shape
Triangle (three sides)
Side a
3 cm
Side b
4 cm
Side c
5 cm
Show results in
Centimetres (cm)
Area
6 cm²
Perimeter
12 cm
Height
4 cm

Checked against: Right triangle with legs 3 and 4: ½·3·4 = 6; height onto side 3 is the other leg, 4

Regular hexagon, side 2 m

Shape
Regular polygon
Side length
2 m
Number of sides
6
Show results in
Metres (m)
Area
10.392305 m²
Perimeter
12 m
Apothem (inradius)
1.732051 m
Circumradius
2 m

Checked against: Python 3.8 math: 6*4/(4*tan(pi/6)) = 6√3, 2/(2*tan(pi/6)) = √3; a hexagon's circumradius equals its side

Square as a regular 4-gon (exact tan 45°)

Shape
Regular polygon
Side length
3 cm
Number of sides
4
Show results in
Centimetres (cm)
Area
9 cm²
Apothem (inradius)
1.5 cm
Circumradius
2.12132 cm

Checked against: Square of side 3: area 9, apothem 3/2; Python 3.8 math: 3/sqrt(2)

Questions

How do you find the area of a trapezoid?

Average the two parallel sides and multiply by the perpendicular height: A = (a + b)/2 × h. Bases of 10 cm and 4 cm with a height of 4 cm give 7 × 4 = 28 cm². British English calls this shape a trapezium; the formula is the same. The perimeter also needs the two slanted legs: legs of 5 cm each make it 24 cm.

How do you find the area of a triangle from three sides?

Use Heron's formula. Take the semi-perimeter s = (a + b + c)/2, then A = √(s(s − a)(s − b)(s − c)). Sides of 5, 6 and 7 cm give s = 9 and A = √(9 × 4 × 3 × 2) = √216 ≈ 14.697 cm². Three lengths only make a triangle if each is shorter than the other two combined, so 3, 4 and 8 have no area.

What is the area of a regular hexagon?

A = (3√3/2)s², about 2.598 times the side squared. A hexagon with 5 cm sides covers 64.952 cm², and one with 2 m sides covers 10.392 m². Any regular polygon with n sides of length s has A = ns²/(4 tan(180°/n)). A hexagon's circumradius equals its side, and its apothem is s√3/2 ≈ 0.866s.

Is there a formula for the perimeter of an ellipse?

Not an exact one in elementary functions: the exact perimeter is a complete elliptic integral. Ramanujan's 1914 approximation, P ≈ π(a + b)(1 + 3h/(10 + √(4 − 3h))) with h = (a − b)²/(a + b)², is off by at most 0.04%, reached only as the ellipse flattens into a line. For semi-axes of 10 and 6 it gives 51.0539977, within 1.2 × 10⁻⁹ of the exact value.

How do you convert square feet to square metres?

Multiply by 0.09290304, the square of the international foot (0.3048 m exactly, fixed in 1959). One square metre is about 10.764 ft². A 12 ft × 10 ft room is 120 ft², or 11.148 m². Area scales with the square of the length unit, so converting each side first and then multiplying gives the same result.

How accurate is the area and perimeter calculator?

Accuracy depends on your inputs and the method's assumptions. Decimal arithmetic uses 50 significant digits, but estimates, numerical methods and source data can be less precise; the displayed rounding does not remove those limits. It is checked against 16 worked examples whose answers come from independent sources; for example, “Rectangle 8 × 5 cm” is checked against 8 × 5, 2(8 + 5); Python 3.8 math.sqrt(89).

Where does the method come from?

Weisstein, E. W. “Heron's Formula”, “Regular Polygon”, “Ellipse” — MathWorld; Ramanujan, S. (1914) “Modular equations and approximations to π”, Quarterly Journal of Mathematics 45, 350–372 (perimeter approximation II); NIST Handbook 44, Appendix C — exact inch–centimetre relation (1 in = 2.54 cm).

About this calculator

A△=s(s−a)(s−b)(s−c),An-gon=ns24tan⁡(π/n)Pellipse≈π(a+b)(1+3h10+4−3h)\begin{gathered} A_\triangle = \sqrt{s(s-a)(s-b)(s-c)},\quad A_{n\text{-gon}} = \frac{n s^2}{4\tan(\pi/n)} \\ P_\text{ellipse} \approx \pi(a+b)\left(1 + \frac{3h}{10 + \sqrt{4-3h}}\right) \end{gathered}

Sources

  1. Weisstein, E. W. “Heron's Formula”, “Regular Polygon”, “Ellipse” — MathWorld
  2. Ramanujan, S. (1914) “Modular equations and approximations to π”, Quarterly Journal of Mathematics 45, 350–372 (perimeter approximation II)
  3. NIST Handbook 44, Appendix C — exact inch–centimetre relation (1 in = 2.54 cm)

Checked against references

16 worked examples with independently sourced answers ship with this calculator. They run in the test suite; you can run them here too.

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