12 V across 6 Ω
- I know
- Voltage and resistance
- Voltage
- 12
- Voltage unit
- V
- Resistance
- 6
- Resistance unit
- Ω
- Show current in
- A
- Show power in
- W
- Current
- 2 A
- Power
- 24 W
Checked against: Python 3.8 decimal: I = 12/6, P = 12²/6
Ohm's law calculator: enter any two of voltage, current, resistance and power to get the other two, shown in the units you pick (mA, kΩ…).
12 V across 6 Ω drives 2 A and turns 24 W into heat.
Ohm's law holds for ohmic conductors (resistance independent of current); diodes, lamps and LEDs are not ohmic.
Ohm's law says the current through a resistor equals the voltage across it divided by its resistance, I = V/R. Combined with the power law P = VI, any two of voltage, current, resistance and power fix the other two: P = I²R and P = V²/R follow by substitution. Solved values are shown in the unit you choose, so a milliamp current does not appear as 0.002 A.
The default, 12 V across 6 Ω, gives 2 A and 24 W. The same arithmetic sizes fuses and cables (a 2,300 W kettle on 230 V draws 10 A) and checks resistor ratings (a 100 Ω, ¼ W resistor carries at most 50 mA).
The law holds for ohmic conductors, whose resistance stays constant as the current changes. Diodes, LEDs and filament lamps are not ohmic, so a single resistance value describes them only at one operating point.
Checked against: Python 3.8 decimal: I = 12/6, P = 12²/6
Checked against: Python 3.8 decimal: R = 230/10, P = 230 × 10
Checked against: Python 3.8 decimal: I = √(0.25/100), V = √(0.25 × 100)
Checked against: Python 3.8 decimal: I = 0.5/5, R = 25/0.5
Divide the voltage by the resistance: I = V/R. With 12 V across 6 Ω the current is 2 A; with 5 V across 1 kΩ it is 0.005 A, or 5 mA. Convert kilohms to ohms (×1,000) before dividing, or pick kΩ and mA in the unit selectors and let the calculator convert.
Divide the power by the voltage: I = P/V. A 2,300 W kettle on a 230 V supply draws 10 A, and a 60 W load on 12 V draws 5 A. For AC this holds for resistive loads such as heaters and kettles; motors and power supplies with a power factor below 1 draw more current than P/V.
P = VI, which becomes P = I²R or P = V²/R once Ohm's law is substituted. A 100 Ω resistor with 5 V across it dissipates 5²/100 = 0.25 W, exactly the limit of a ¼ W part, so a 0.5 W resistor is the safer choice there.
Not with a single fixed resistance. An LED conducts almost nothing below its forward voltage (about 2 V for red, about 3 V for blue and white) and then current rises steeply, so it needs a series resistor. A filament lamp's resistance rises as the tungsten heats, so the V²/P value, 882 Ω for a 60 W, 230 V bulb, applies only when it is lit.
Conductance is the reciprocal of resistance, G = 1/R, measured in siemens (S). A 6 Ω resistor has a conductance of 1/6 ≈ 0.167 S. Conductances in parallel add directly, which is why it is convenient for parallel networks: 1/R_total = G₁ + G₂ + …
Accuracy depends on your inputs and the method's assumptions. Decimal arithmetic uses 50 significant digits, but estimates, numerical methods and source data can be less precise; the displayed rounding does not remove those limits. It is checked against 6 worked examples whose answers come from independent sources; for example, “12 V across 6 Ω” is checked against Python 3.8 decimal: I = 12/6, P = 12²/6.
OpenStax University Physics Volume 2, §9.4 Ohm's law and §9.5 Electrical energy and power; HyperPhysics — Ohm's law, power.
6 worked examples with independently sourced answers ship with this calculator. They run in the test suite; you can run them here too.
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