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Voltage drop and AWG wire gauge calculator

Voltage drop over a DC, single-phase or three-phase cable run, plus AWG wire size to diameter, mm², kcmil and resistance per km, and back.

Drafted with AI writing toolsUpdated Checked examples: 6

V
Try
Voltage drop
%
Voltage drop: 3.91 %
Decimal places: 2; Nearest, ties to even
Voltage drop
4.68962V
Voltage at the load
115.31V
Power lost in the wire
70.3444W
Nearest AWG
12 AWG
Diameter
2.05253mm / 0.0808081in
Cross-section area
3.30877mm² / 6.52995kcmil
Resistance at 20 °C
5.211Ω/km / 1.588Ω/kft
Resistance is for solid copper at 20 °C; at a 75 °C conductor temperature it is about 22% higher.
Above the 3% branch-circuit guidance (NEC 210.19(A) note) but within 5% overall.

30 m of 12 AWG copper carrying 15 A drops 4.69 V (3.91% of 120 V), leaving 115.31 V at the load and wasting 70.34 W as heat.

Voltage drop against the usual limits

≤ 3% branch3–5%> 5%035123.91%
How it's calculated S
  1. Diameter from the gauge number

    d=0.005 in×92(36−(12))/39=0.0808081 in=2.05253 mmd = 0.005\,\text{in}\times 92^{(36 - (12))/39} = 0.0808081\ \mathrm{in} = 2.05253\ \mathrm{mm}
  2. Area and resistance

    A=πd24=3.30877 mm2,R′=ρA=1.7241×10−80.00000330877=5.21069 Ω/kmA = \frac{\pi d^2}{4} = 3.30877\ \mathrm{mm^2},\quad R' = \frac{\rho}{A} = \frac{1.7241 \times 10^{-8}}{0.00000330877} = 5.21069\ \mathrm{\Omega/km}
  3. Voltage drop

    ΔV=2 IR′L=2(15)(0.00521069)(30)=4.68962 V\Delta V = 2\,I R' L = 2(15)(0.00521069)(30) = 4.68962\ \mathrm{V}

    The current flows out and back, so the wire length counts twice; reactance is ignored.

  4. As a share of the supply

    4.68962120×100=3.908%\frac{4.68962}{120}\times100 = 3.908\%
  5. Power lost in the conductors

    P=2 I2R′L=70.3444 WP = 2\,I^2R'L = 70.3444\ \mathrm{W}

About the voltage drop and AWG wire gauge calculator

Voltage drop is the voltage lost along a cable because the conductor has resistance. The calculator takes the resistance per metre from the cross-section (R′ = ρ/A, with ρ at 20 °C) and multiplies it by the current and the one-way length: twice for DC and single-phase, because the current goes out and back, and by √3 for a balanced three-phase run. It also converts any AWG size to diameter, mm², kcmil and ohms per km with the ASTM B258 formula, or finds the nearest AWG for a measured diameter.

The default, 15 A over 30 m of 12 AWG copper at 120 V, drops 4.69 V, or 3.91%. That is above the 3% branch-circuit figure in the NEC informational note; 10 AWG brings the same run down to 2.46%.

The result is a resistive estimate at 20 °C. Copper's resistance is about 22% higher at a 75 °C operating temperature, and long AC runs of large cables add reactance, so leave a margin when the result is close to a limit.

How to calculate voltage drop in a wire

For DC or single-phase AC, ΔV = 2 × I × R′ × L, where R′ is the wire's resistance per meter and L the one-way length. 15 A over 30 m of 12 AWG copper (5.211 Ω/km at 20 °C) drops 2 × 15 × 0.005211 × 30 = 4.69 V, which is 3.91% of 120 V.

Voltage drop step by step

  1. Resistance per meter: R′ = ρ/A. 12 AWG copper has A = 3.3088 mm², and annealed copper's resistivity at 20 °C is 0.017241 Ω·mm²/m (IEC 60028), so R′ = 0.005211 Ω/m.
  2. Both conductors: current goes out and comes back, so a 30 m run puts 60 m of wire in the circuit.
  3. Drop in volts: 2 × 15 A × 0.005211 Ω/m × 30 m = 4.69 V.
  4. Drop in percent: 4.69 ÷ 120 × 100 = 3.91%, leaving 115.31 V at the load.
  5. Heat in the wire: I²R summed over both conductors, which equals ΔV × I: 4.69 V × 15 A = 70.3 W.

For a balanced three-phase load, use ΔV = √3 × I × R′ × L with the line current, and compare the result with the line-to-line voltage. 60 A over 50 m of 4 AWG aluminum at 400 V drops 6.94 V, or 1.74%.

AWG wire sizes and resistance

ASTM B258 defines the gauge by formula: d = 0.005 in × 92^((36 − n)/39), with 1/0 to 4/0 counted as n = 0 to −3. That makes 36 AWG exactly 0.005 in and 4/0 exactly 0.46 in.

Each gauge number changes the diameter by a factor of 1.1229, so three gauge numbers double or halve the area. Solid copper at 20 °C:

  • 18 AWG: 1.024 mm, 0.823 mm², 20.95 Ω/km (6.385 Ω per 1,000 ft)
  • 16 AWG: 1.291 mm, 1.309 mm², 13.17 Ω/km (4.015 Ω per 1,000 ft)
  • 14 AWG: 1.628 mm, 2.081 mm², 8.285 Ω/km (2.525 Ω per 1,000 ft)
  • 12 AWG: 2.053 mm, 3.309 mm², 5.211 Ω/km (1.588 Ω per 1,000 ft)
  • 10 AWG: 2.588 mm, 5.261 mm², 3.277 Ω/km (0.9988 Ω per 1,000 ft)
  • 8 AWG: 3.264 mm, 8.366 mm², 2.061 Ω/km (0.6282 Ω per 1,000 ft)
  • 6 AWG: 4.115 mm, 13.30 mm², 1.296 Ω/km (0.3951 Ω per 1,000 ft)

NIST's historic wire-gage table and Wikipedia's AWG table give nominal diameters and areas to compare. Area in kcmil is the diameter in mils squared, divided by 1,000; a mil is a thousandth of an inch.

To identify a measured wire, invert the formula: n = 36 − 39 × log₉₂(d / 0.127 mm). A 2.05 mm conductor gives n = 12.01, so it is 12 AWG. Measure the bare metal; the insulation's outside diameter says nothing about the gauge.

Copper or aluminum wire

Electrical-grade aluminum has a resistivity of 0.028264 Ω·mm²/m at 20 °C (61% IACS, IEC 60889), 1.64 times copper's. The same 15 A, 30 m run in 12 AWG drops 6.41% in aluminum against 3.91% in copper.

Matching copper's resistance takes about 1.6 times the cross-section, roughly two AWG sizes larger. Aluminum terminations need connectors rated for aluminum.

Is 3% voltage drop the limit?

An informational note to NEC 210.19(A) recommends at most 3% on a branch circuit and 5% for feeder and branch combined. The note is advice, though some jurisdictions adopt it.

The rows below are the 12 AWG copper run above (Default), the same run in 10 AWG (Larger wire), and the same run carrying no current (No current).

ScenarioVoltage drop
Default3.91%
Larger wire2.46%
No current0.00%

12 AWG misses the 3% branch figure and 10 AWG meets it. With no current there is no drop at all, because ΔV is proportional to I.

How long can a wire run be?

Rearrange for the longest one-way run within a limit, written as a fraction: L = (limit × V)/(2 × I × R′). At 15 A on 120 V with a 3% limit, 12 AWG copper reaches 23.03 m (75.6 ft) and 10 AWG reaches 36.62 m (120.1 ft).

Voltage drop is only half of wire sizing

A wire can pass a voltage-drop check and still be too small to carry its current safely. Size the conductor first for ampacity, insulation temperature rating and terminal ratings under your electrical code, then check the drop.

The drop itself is a resistive estimate at 20 °C. A copper conductor running at 75 °C has about 22% more resistance, and long AC runs of large cables add reactance, so leave margin when a result is close to a limit.

Common mistakes

  • Entering the round-trip length. The one-way length is doubled for the return conductor. Typing 60 m for a 30 m run reports 7.82% instead of 3.91%.
  • Mixing three-phase voltages. The √3 formula pairs line current with line-to-line voltage, such as 400 V; dividing by the phase-to-neutral voltage overstates the percentage.
  • Forgetting the feeder. The 5% overall figure covers feeder and branch together, so a branch at 3% leaves 2% for everything upstream.

Inputs worth checking

  • Length is one-way, in meters, feet or kilometers.
  • 1/0 to 4/0 are the sizes also written 0, 00, 000 and 0000.
  • Diameter accepts millimeters, inches or mils, measured on the bare conductor.

The Ohm's law calculator checks the current and resistance behind a drop. To price the watts a cable wastes, use the electricity cost calculator.

Worked examples

12 AWG copper

Calculate
AWG → size
Wire gauge (AWG)
12 AWG
Conductor
Copper
Diameter
2.05253 mm
Cross-section area
3.30877 mm²
Resistance at 20 °C
5.211 Ω/km

Checked against: 0.005 in × 92^(24/39) = 2.0525254 mm; ρ/A with ρ = 1.7241e-8 Ω·m (AWG table: 2.053 mm, 3.31 mm², 5.211 Ω/km)

4/0 AWG is exactly 0.46 in

Calculate
AWG → size
Wire gauge (AWG)
4/0 (0000)
Conductor
Copper
Diameter
0.46 in
Cross-section area
211.6 kcmil

Checked against: ASTM B258 definition: 4/0 = 0.4600 in = 211.6 kcmil

36 AWG is exactly 0.005 in

Calculate
AWG → size
Wire gauge (AWG)
36 AWG
Conductor
Copper
Diameter
0.127 mm
Cross-section area
0.025 kcmil

Checked against: ASTM B258 definition: 36 AWG = 0.0050 in

2.05 mm wire

Calculate
Diameter → AWG
Conductor diameter
2.05 mm
Conductor
Copper
Nearest AWG
12 AWG
Exact gauge number
12.01

Checked against: n = 36 − 39·log₉₂(2.05/0.127) = 12.0106

Questions

What is the maximum allowed voltage drop?

In the US, an informational note to NEC 210.19 recommends at most 3% on a branch circuit and 5% in total for feeder plus branch circuit. The note is advice, not an enforceable rule, although some jurisdictions adopt it. IEC 60364-5-52 and BS 7671 give 3% for lighting and 5% for other loads when the installation is fed from a public low-voltage network, and 6% and 8% from a private supply.

How do you calculate voltage drop in a wire?

Multiply the current by the resistance of the wire that carries it. For DC or single-phase, ΔV = 2 × I × R′ × L, where R′ is the resistance per metre and L the one-way length; the 2 counts the outgoing and return conductors. For balanced three-phase, use √3 (1.732) instead of 2 and compare the result with the line-to-line voltage. 15 A over 30 m of 12 AWG copper (5.21 Ω/km) drops 4.69 V.

How does the AWG number relate to wire diameter?

ASTM B258 defines AWG by a formula: 36 AWG is 0.005 in and 4/0 (0000) is 0.46 in, with 39 equal ratio steps between them, so each gauge number changes the diameter by a factor of 1.1229. Three gauge numbers double or halve the cross-sectional area, and six double or halve the diameter. 12 AWG is 2.053 mm across with 3.31 mm² of metal.

Why is this resistance lower than in NEC Chapter 9 Table 8?

Table 8 lists DC resistance at 75 °C, while this calculator uses solid conductors at 20 °C with copper's resistivity from IEC 60028 (0.017241 Ω·mm²/m). For solid 12 AWG copper, Table 8 gives 1.93 Ω per 1000 ft against 1.59 here; the whole difference is the 55 °C of extra temperature. Stranded 12 AWG is listed slightly higher, at 1.98 Ω per 1000 ft.

How much bigger does an aluminium wire need to be than copper?

About 1.6 times the cross-section, or roughly two AWG sizes larger, for the same resistance and voltage drop. Electrical-grade aluminium conducts 61% as well as copper (IEC 60889), with a resistivity of 0.028264 Ω·mm²/m against copper's 0.017241. The final size must also meet the ampacity tables, and aluminium terminations need connectors rated for it.

About this calculator

d=0.005 in×92(36−n)/39,R′=ρA,ΔV=k IR′L, k=2 (DC, 1-phase), 3 (3-phase)d = 0.005\,\text{in}\times 92^{(36-n)/39},\quad R' = \frac{\rho}{A},\quad \Delta V = k\,I R' L,\ k = 2\ (\text{DC, 1-phase}),\ \sqrt3\ (\text{3-phase})

Sources

  1. ASTM B258 — Standard specification for standard nominal diameters and cross-sectional areas of AWG sizes
  2. IEC 60028 — International standard of resistance for copper (0.017241 Ω·mm²/m at 20 °C)
  3. NFPA 70 (NEC) 210.19(A) Informational Note — 3% branch / 5% total voltage drop guidance
  4. Wikipedia — American wire gauge (table of diameters, areas and copper resistance)

Checked against references

This calculator includes 6 worked examples with independently sourced answers. They run in the test suite, and you can run them here too.

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