温度换算

用 °F = °C × 9/5 + 32 换算摄氏度与华氏度，并将两者换算为开尔文。支持兰氏度和列氏度；拒绝低于绝对零度的值。

更新于 2026年9月29日已验证的示例：5

转换后的数值

°F

有效数字：12；取最近值，等距时远离零

换算: 37 °C = 98.6 °F
精确性: 精确

37 °C精确等于98.6 °F。

温度计上的位置

37 °C用各个温度单位表示行数：5

单位	数值	定义
开尔文 (K)	310.15	基本单位
摄氏度 (°C)	37	K = °C + 273.15，精确值
华氏度 (°F)	98.6	K = (°F + 459.67) × 5/9，精确值
degree Rankine (°R)	558.27	1 °R = 5/9 K，精确值
degree Réaumur (°Ré)	29.6	K = (°Ré + 218.52) × 5/4，精确值

计算方法 S

将摄氏度换算为开尔文
$37 + 273.15 = 310.15\ \text{K}$
K = °C + 273.15，精确值
将开尔文换算为华氏度
$310.15 \div \tfrac{5}{9} - 459.67 = 98.6\ \text{°F}$
K = (°F + 459.67) × 5/9，精确值
除换算系数外，还需加上偏移量
温标的零点不同，因此换算时除缩放外还需要加上偏移量。1 °C的温差等于1.8 °F。
两个单位的定义都精确，且换算结果为有限小数，因此显示的每一位数字都精确。

关于温度换算

Temperature scales differ in the size of a degree and in where zero sits, so a conversion adds an offset as well as multiplying: °F = °C × 9/5 + 32, and K = °C + 273.15. The converter works through kelvin, whose zero is absolute zero, and rejects any value below it (−273.15 °C or −459.67 °F).

The default converts normal body temperature: 37 × 9/5 + 32 = 98.6 °F. Weather forecasts, oven settings and fever readings are the everyday uses; the 38 °C fever threshold is 100.4 °F.

A temperature difference converts without the offset: a rise of 10 °C is a rise of 18 °F. Rankine is the absolute scale with Fahrenheit-sized degrees, and Réaumur is a historical scale with 80 degrees between the freezing and boiling points of water.

计算示例

Body temperature, 37 °C in °F

数值: 37 °C
从: degree Celsius (°C)
到: degree Fahrenheit (°F)

转换后的数值: 98.6 °F
换算: 37 °C = 98.6 °F
精确性: 精确

核验来源：°F = °C × 9/5 + 32 (NIST SP 811 §4.2.1.1): 37 × 1.8 + 32 = 98.6

−40 is the same in both scales

数值: -40 °C
从: degree Celsius (°C)
到: degree Fahrenheit (°F)

转换后的数值: -40 °F

核验来源：−40 × 9/5 + 32 = −40

Absolute zero in °F

数值: 0 K
从: kelvin (K)
到: degree Fahrenheit (°F)

转换后的数值: -459.67 °F
精确性: 精确

核验来源：0 K = −273.15 °C; −273.15 × 9/5 + 32 = −459.67 °F (NIST SP 811 App. B.9)

100 °F in °C

数值: 100 °F
从: degree Fahrenheit (°F)
到: degree Celsius (°C)

转换后的数值: 37.7777777778 °C
精确性: 定义精确，结果为循环小数

核验来源：(100 − 32) × 5/9 = 340/9 (Python 3.8 fractions from the legal definitions)

常见问题

How do I convert Celsius to Fahrenheit?

Multiply by 9/5 (1.8) and add 32. For 37 °C, 37 × 1.8 = 66.6, and adding 32 gives 98.6 °F. To go back, subtract 32 and multiply by 5/9: (100 °F − 32) × 5/9 = 37.78 °C. NIST SP 811 states the same relation as t/°F = 1.8 t/°C + 32.

Is 98.6 °F normal body temperature?

98.6 °F is the exact Fahrenheit value of 37 °C, the average Carl Wunderlich published in 1868; individual readings vary with the person, the time of day and where the thermometer goes. For illness the threshold matters more: the NHS treats 38 °C or above as a high temperature, and the US CDC defines fever as 100.4 °F, the same value.

At what temperature are Celsius and Fahrenheit equal?

At −40. Setting the two numbers equal in °F = °C × 9/5 + 32 gives x = 1.8x + 32, so x = −40, and −40 °C is exactly −40 °F. It is the only crossing point because the degrees differ in size; above −40 the Fahrenheit number is always the larger one.

How do I convert Celsius to kelvin?

Add 273.15: 25 °C is 298.15 K, and absolute zero, 0 K, is −273.15 °C. A kelvin is the same size as a Celsius degree and, since 2019, is defined by fixing the Boltzmann constant at 1.380649 × 10⁻²³ J/K (BIPM SI Brochure). Kelvin is written without a degree sign.

Why is a 10 °C rise an 18 °F rise and not 50 °F?

Because a difference has no zero point to shift. One Celsius degree is 1.8 Fahrenheit degrees, so a change of 10 °C is a change of 18 °F; the +32 applies only to a reading on the scale. The converter's steps show the offset and the per-degree factor separately for this reason.

“温度换算”有多准确？

准确性取决于输入值和方法的假设。十进制运算使用50位有效数字，但估算、数值方法和源数据的精度可能较低；显示时的舍入并不能消除这些限制。已按独立来源核验的计算示例：5。例如，“Body temperature, 37 °C in °F”根据°F = °C × 9/5 + 32 (NIST SP 811 §4.2.1.1): 37 × 1.8 + 32 = 98.6进行核验。

这种方法出自哪里？

NIST SP 811 (2008), Guide for the Use of the SI, Appendix B — conversion factors; NIST Handbook 44, Appendix C — General tables of units of measurement; BIPM SI Brochure, 9th edition (2019), §2.3.1 — the kelvin and degree Celsius.

关于此计算器

\begin{gathered} t_{\text{°F}} = t_{\text{°C}} \times \tfrac{9}{5} + 32 \\ T_{\text{K}} = t_{\text{°C}} + 273.15 \\ T_{\text{°R}} = T_{\text{K}} \times \tfrac{9}{5} \\ t_{\text{°Ré}} = t_{\text{°C}} \times \tfrac{4}{5} \end{gathered}

来源

已对照来源验证

此计算器包含 5 个已解示例，答案来自独立来源。这些示例会在测试套件中运行，你也可以在此运行验证。