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Slope, distance and midpoint calculator: line through two points

Distance, midpoint and slope between two points, the line's equation in slope-intercept, standard and point-slope form, and where two lines meet.

Updated Checked against 6 worked examples

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Distance P₁P₂
Distance P₁P₂: 5
Shown to up to 8 decimal places, half-up
Midpoint x
2.5
Midpoint y
4
Slope
1.33333333
Angle of inclination
53.1301°
Slope-intercept form
y = (4/3)x + 2/3
Standard form
4x − 3y = −2
Point-slope form
y − 2 = (4/3)(x − 1)
Perpendicular bisector
y = −0.75x + 5.875

P₁(1, 2) and P₂(4, 6) are 5 apart with midpoint (2.5, 4); the line through them has slope 4/3 (rising at 53.13°).

Points and lines

d = 5P₁(1, 2)P₂(4, 6)M(2.5, 4)
How it's calculated S
  1. Distance

    d=(4−1)2+(6−2)2=25=5d = \sqrt{(4 - 1)^2 + (6 - 2)^2} = \sqrt{25} = 5
  2. Midpoint

    M=(x1+x22,y1+y22)=(2.5,4)M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) = (2.5, 4)
  3. Slope

    m=y2−y1x2−x1=43=4/3m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4}{3} = 4/3

    Angle of inclination: arctan m = 53.1301°.

  4. Line through the points

    Slope-intercept: y = (4/3)x + 2/3 · Standard: 4x − 3y = −2 · Point-slope: y − 2 = (4/3)(x − 1)

  5. Perpendicular bisector

    Through M(2.5, 4) at right angles to P₁P₂: y = −0.75x + 5.875.

About the slope, distance and midpoint calculator

Enter two points to get the straight-line distance d = √((x₂ − x₁)² + (y₂ − y₁)²), the midpoint ((x₁ + x₂)/2, (y₁ + y₂)/2) and the slope m = (y₂ − y₁)/(x₂ − x₁). The line through them is written in slope-intercept form y = mx + b, in standard form Ax + By = C with whole-number coefficients and in point-slope form, alongside its perpendicular bisector. Fractions stay exact, so a slope of 4/3 is not rounded to 1.3333.

The default points (1, 2) and (4, 6) are 5 apart, a 3-4-5 triangle, with midpoint (2.5, 4) and line y = (4/3)x + 2/3. Switching on a second line adds whether the two are parallel, perpendicular or intersecting, the angle between them and the crossing point.

A vertical line has no slope, so only its standard form, such as x = 3, is given. Coordinates carry no unit: the distance is in whatever unit they use.

Worked examples

P₁(1, 2) and P₂(4, 6)

Point 1: x
1
Point 1: y
2
Point 2: x
4
Point 2: y
6
Distance P₁P₂
5
Midpoint x
2.5
Midpoint y
4
Slope
1.33333333
Angle of inclination
53.130102 °
Slope-intercept form
y = (4/3)x + 2/3
Standard form
4x − 3y = −2
Point-slope form
y − 2 = (4/3)(x − 1)
Perpendicular bisector
y = −0.75x + 5.875

Checked against: Python 3.8 fractions: dx = 3, dy = 4 (3-4-5), m = 4/3, b = 2 − 4/3 = 2/3; bisector through (5/2, 4) with slope −3/4 has b = 47/8 = 5.875 (terminating fractions print as decimals); math.degrees(atan(4/3))

Vertical line (edge case: no slope)

Point 1: x
3
Point 1: y
1
Point 2: x
3
Point 2: y
7
Distance P₁P₂
6
Standard form
x = 3
Angle of inclination
90 °
Perpendicular bisector
y = 4
Midpoint y
4

Checked against: Equal x-coordinates: the line x = 3 is vertical; the bisector is the horizontal line through (3, 4)

Decimal coordinates

Point 1: x
-1.5
Point 1: y
2.25
Point 2: x
3.5
Point 2: y
-0.75
Distance P₁P₂
5.83095189
Slope
-0.6
Slope-intercept form
y = −0.6x + 1.35
Standard form
12x + 20y = 27

Checked against: Python 3.8 fractions: dx = 5, dy = −3, √34; −3x − 5y = −27/4 scaled by −4

Two intersecting lines

Point 1: x
1
Point 1: y
2
Point 2: x
4
Point 2: y
6
Compare with a second line
yes
Line 2, point 3: x
0
Line 2, point 3: y
6
Line 2, point 4: x
6
Line 2, point 4: y
0
The lines are
Intersecting
Angle between the lines
81.869898 °
Intersection x
2.28571429
Intersection y
3.71428571
Line 2
y = −x + 6

Checked against: tan θ = |(−1 − 4/3)/(1 − 4/3)| = 7, Python 3.8 math.degrees(atan(7)); intersection (16/7, 26/7) by Python fractions

Questions

How do you find the slope between two points?

Divide the change in y by the change in x: m = (y₂ − y₁)/(x₂ − x₁). From (1, 2) to (4, 6) the rise is 4 and the run is 3, so m = 4/3 ≈ 1.3333. A positive slope rises to the right, a negative one falls, 0 is horizontal, and when x₂ = x₁ the line is vertical and the slope is undefined.

What is the distance formula?

d = √((x₂ − x₁)² + (y₂ − y₁)²), which is Pythagoras' theorem applied to the horizontal and vertical gaps. Between (1, 2) and (4, 6) the gaps are 3 and 4, so d = √25 = 5. For points given as latitude and longitude use a great-circle formula instead, because the flat formula ignores the Earth's curvature.

How do you find the equation of a line through two points?

Find the slope m, then the intercept b = y₁ − m·x₁, and write y = mx + b. Through (1, 2) and (4, 6), m = 4/3 and b = 2 − 4/3 = 2/3, so y = (4/3)x + 2/3. Multiplying by 3 and rearranging gives the standard form 4x − 3y = −2, with whole-number coefficients.

How do you tell if two lines are parallel or perpendicular?

Compare their slopes. Parallel lines have equal slopes, and perpendicular lines have slopes whose product is −1, such as 1/2 and −2. Any other pair crosses at an angle θ with tan θ = |(m₂ − m₁)/(1 + m₁m₂)|: slopes of 4/3 and −1 give tan θ = 7, so the lines meet at 81.87°.

What is a perpendicular bisector?

The line through the midpoint of a segment at right angles to it; every point on it is equally far from both endpoints. For (1, 2) and (4, 6) it passes through (2.5, 4) with slope −3/4, the negative reciprocal of 4/3, giving y = −0.75x + 5.875. The bisectors of a triangle's three sides meet at the centre of its circumscribed circle.

How accurate is the slope, distance and midpoint calculator?

Accuracy depends on your inputs and the method's assumptions. Decimal arithmetic uses 50 significant digits, but estimates, numerical methods and source data can be less precise; the displayed rounding does not remove those limits. It is checked against 6 worked examples whose answers come from independent sources; for example, “P₁(1, 2) and P₂(4, 6)” is checked against Python 3.8 fractions: dx = 3, dy = 4 (3-4-5), m = 4/3, b = 2 − 4/3 = 2/3; bisector through (5/2, 4) with slope −3/4 has b = 47/8 = 5.875 (terminating fractions print as decimals); math.degrees(atan(4/3)).

Where does the method come from?

OpenStax College Algebra 2e, §2.1 (distance and midpoint formulas) and §2.2 (equations of lines); Weisstein, E. W. “Line”, “Perpendicular Bisector” — MathWorld.

About this calculator

d=(x2−x1)2+(y2−y1)2,M=(x1+x22,y1+y22),m=y2−y1x2−x1,tan⁡θ=∣m2−m11+m1m2∣d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2},\quad M = \left(\tfrac{x_1 + x_2}{2}, \tfrac{y_1 + y_2}{2}\right),\quad m = \frac{y_2 - y_1}{x_2 - x_1},\quad \tan\theta = \left|\frac{m_2 - m_1}{1 + m_1 m_2}\right|

Sources

  1. OpenStax College Algebra 2e, §2.1 (distance and midpoint formulas) and §2.2 (equations of lines)
  2. Weisstein, E. W. “Line”, “Perpendicular Bisector” — MathWorld

Checked against references

6 worked examples with independently sourced answers ship with this calculator. They run in the test suite; you can run them here too.

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