1 g in m/s²
- Value
- 1 g
- From
- standard gravity (g)
- To
- metre per second squared (m/s²)
- Converted value
- 9.80665 m/s²
Checked against: Standard gravity g₀ = 9.80665 m/s² exactly (CGPM 1901)
Convert g-force to m/s², m/s² to g, ft/s² and gal (cm/s²), using standard gravity g₀ = 9.80665 m/s² exactly.
1 g is exactly 9.80665 m/s².
| Unit | Value | Definition |
|---|---|---|
| metre per second squared (m/s²) | 9.80665 | Base unit |
| standard gravity (g) | 1 | 1 g = 9.80665 m/s², exact |
| foot per second squared (ft/s²) | 32.17405 | 1 ft/s² = 0.3048 m/s², exact |
| gal (galileo) | 980.665 | 1 Gal = 0.01 m/s², exact |
1 g = 9.80665 m/s², exact. Both units are defined exactly and the converted value is a terminating decimal, so every digit shown in it is exact.
Acceleration is change of speed per unit time, and each unit here is a fixed number of metres per second squared. The g of g-force is standard gravity, g₀ = 9.80665 m/s², fixed by the 3rd CGPM in 1901; a foot per second squared is 0.3048 m/s², and a gal (galileo) is 1 cm/s².
The default converts 1 g to 9.80665 m/s². Vehicle performance is the everyday use: a car that reaches 100 km/h from rest in 3 seconds averages 9.26 m/s², or 0.94 g.
Standard gravity is a conventional value. Real free-fall acceleration runs from about 9.78 m/s² at the equator to 9.83 m/s² at the poles, and geophysicists measure its local variations in milligals.
Checked against: Standard gravity g₀ = 9.80665 m/s² exactly (CGPM 1901)
Checked against: 9.80665 / 0.3048 = 196133/6096 (Python 3.8 fractions from the legal definitions)
Checked against: 1 Gal = 1 cm/s² (NIST SP 811 App. B)
Checked against: Definition of g₀
Exactly 9.80665 m/s², the standard acceleration of gravity adopted by the 3rd General Conference on Weights and Measures in 1901. It equals 32.174 ft/s². Local gravity differs slightly; 9.80665 is the convention used for g-force and for units such as the kilogram-force.
Divide the speed gained by the time, then divide by 9.80665. 0–60 mph (26.8224 m/s) in 3 s averages 8.94 m/s², or 0.91 g; 0–100 km/h (27.78 m/s) in 3 s averages 9.26 m/s², or 0.94 g. The peak acceleration during the run is higher than this average.
One centimetre per second squared, 0.01 m/s², named after Galileo. Earth's surface gravity is about 980 Gal, so gravity surveys work in milligals, where 1 mGal is about one millionth of g. The symbol is Gal, and the unit has nothing to do with the gallon.
Multiply by 0.3048, the exact number of metres in a foot. 32.174 ft/s² is 9.80665 m/s² (1 g), and 10 ft/s² is 3.048 m/s². To go from m/s² to ft/s², divide by 0.3048, which is the same as multiplying by 3.28084.
No. Free-fall acceleration is about 9.780 m/s² at the equator and 9.832 m/s² at the poles, because the Earth spins and bulges at the equator, and it falls slightly with altitude. 9.81 is 9.80665 rounded, the conventional value between those extremes that g-force is measured against.
Accuracy depends on your inputs and the method's assumptions. Decimal arithmetic uses 50 significant digits, but estimates, numerical methods and source data can be less precise; the displayed rounding does not remove those limits. It is checked against 4 worked examples whose answers come from independent sources; for example, “1 g in m/s²” is checked against Standard gravity g₀ = 9.80665 m/s² exactly (CGPM 1901).
NIST SP 811 (2008), Guide for the Use of the SI, Appendix B — conversion factors; NIST Handbook 44, Appendix C — General tables of units of measurement.
4 worked examples with independently sourced answers ship with this calculator. They run in the test suite; you can run them here too.
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