1 g in m/s²
- Value
- 1 g
- From
- standard gravity (g)
- To
- metre per second squared (m/s²)
- Converted value
- 9.80665 m/s²
Checked against: Standard gravity g₀ = 9.80665 m/s² exactly (CGPM 1901)
Convert g-force to m/s², m/s² to g, ft/s² and gal (cm/s²), using standard gravity g₀ = 9.80665 m/s² exactly.
By AdminDrafted with AI writing toolsUpdated Checked examples: 4
1 g is exactly 9.80665 m/s².
| Unit | Value | Definition |
|---|---|---|
| metre per second squared (m/s²) | 9.80665 | Base unit |
| standard gravity (g) | 1 | 1 g = 9.80665 m/s², exact |
| foot per second squared (ft/s²) | 32.17405 | 1 ft/s² = 0.3048 m/s², exact |
| gal (galileo) | 980.665 | 1 Gal = 0.01 m/s², exact |
1 g = 9.80665 m/s², exact
Both units are defined exactly and the converted mathematical value has a terminating decimal. A displayed result may still be rounded.
Acceleration is change of speed per unit time, and each unit here is a fixed number of metres per second squared. The g of g-force is standard gravity, g₀ = 9.80665 m/s², fixed by the 3rd CGPM in 1901; a foot per second squared is 0.3048 m/s², and a gal (galileo) is 1 cm/s².
The default converts 1 g to 9.80665 m/s². Vehicle performance is the everyday use: a car that reaches 100 km/h from rest in 3 seconds averages 9.26 m/s², or 0.94 g.
Standard gravity is a conventional value. Real free-fall acceleration runs from about 9.78 m/s² at the equator to 9.83 m/s² at the poles, and geophysicists measure its local variations in milligals.
Multiply g by 9.80665, the exact value of standard gravity in m/s². So 2 g = 19.6133 m/s² and 0.5 g = 4.903325 m/s². Divide by 9.80665 to go from m/s² to g. The factor holds for any g-force figure: car tests, rides or accelerometer logs.
Each unit is a fixed number of meters per second squared, as listed in NIST's acceleration conversion tables:
To convert between any two, multiply by the factor of the unit you have and divide by the factor of the unit you want. For 1 g in ft/s²: 9.80665 ÷ 0.3048 = 32.1740485564… ft/s², a repeating decimal.
| Value | From | To | Converted acceleration |
|---|---|---|---|
| 1 | g | m/s² | 9.80665 |
| 9.80665 | m/s² | g | 1 |
| 1 | g | ft/s² | 32.174049 |
| 10 | ft/s² | m/s² | 3.048 |
| 1 | Gal | m/s² | 0.01 |
| 1 | m/s² | Gal | 100 |
The ft/s² value is rounded to six decimal places. Every other row is exact.
Average acceleration is the speed gained divided by the time taken. Put the speed in m/s, divide by the seconds, then divide by 9.80665 to get g:
The same run in 4 seconds averages 6.7056 m/s², about 0.68 g. A 0–60 time gives only the average: the peak during the run is higher unless the push was perfectly steady.
Braking works the same way with a minus sign. Stopping from 60 mph in 4 seconds averages −6.7056 m/s², about −0.68 g. The sign shows the acceleration points against the direction of travel.
The speed converter turns km/h or knots into m/s. When distance is part of the problem, the kinematics calculator solves the constant-acceleration (SUVAT) equations.
The g in g-force is a fixed reference, not the gravity where you stand. Real free-fall acceleration is about 9.780 m/s² at the equator and 9.832 m/s² at the poles, because Earth spins and bulges at the equator.
Measured against standard gravity, those are about 0.997282 g and 1.002585 g. The familiar 9.81 m/s² is 9.80665 rounded and sits 0.034% high. Rounding g to 10 m/s² makes every answer 1.97% high.
The gal is 1 cm/s², named after Galileo, and its symbol Gal has nothing to do with gallons. 100 Gal is 1 m/s², about 0.101972 g.
Earth's surface gravity is about 980 Gal, so gravity surveys measure local differences in milligals. One mGal is 0.00001 m/s², about a millionth of g.
2 g-force, 2 gee and 9.81 m/s^2 are all accepted.25/1000 Gal.Checked against: Standard gravity g₀ = 9.80665 m/s² exactly (CGPM 1901)
Checked against: 9.80665 / 0.3048 = 196133/6096
Checked against: 1 Gal = 1 cm/s² (NIST SP 811 App. B)
Checked against: Definition of g₀
Exactly 9.80665 m/s², the standard acceleration of gravity adopted by the 3rd General Conference on Weights and Measures in 1901. It is approximately 32.174 ft/s². Local gravity differs slightly; 9.80665 is the convention used for g-force and for units such as the kilogram-force.
Divide the speed gained by the time, then divide by 9.80665. 0–60 mph (26.8224 m/s) in 3 s averages 8.94 m/s², or 0.91 g; 0–100 km/h (27.78 m/s) in 3 s averages 9.26 m/s², or 0.94 g. Peak acceleration during the run is at least the average and can be higher.
One centimetre per second squared, 0.01 m/s², named after Galileo. Earth's surface gravity is about 980 Gal, so gravity surveys work in milligals, where 1 mGal is about one millionth of g. The symbol is Gal, and the unit has nothing to do with the gallon.
Multiply by 0.3048, the exact number of metres in a foot. 32.174 ft/s² is approximately 9.80665 m/s² (1 g), and 10 ft/s² is exactly 3.048 m/s². To go from m/s² to ft/s², divide by 0.3048, equivalent to multiplying by approximately 3.28084.
No. Free-fall acceleration is about 9.780 m/s² at the equator and 9.832 m/s² at the poles, because the Earth spins and bulges at the equator, and it falls slightly with altitude. 9.81 is 9.80665 rounded, the conventional value between those extremes that g-force is measured against.
This calculator includes 4 worked examples with independently sourced answers. They run in the test suite, and you can run them here too.